Question

鉴于以下示例查询，在给定一组要排除的范围的情况下，计算日期范围内的总天数的声音和执行方法是什么，假设这些范围可能具有重叠的日期？

更简单地说，我有一个表格，其中包含一组日期范围，其中关闭计费，我从一个日期范围（比如Jan1 - Jan31）开始，我需要确定该范围内发生了多少可计费天数。只是日期的日期减去残疾人日期的日期总和。但是，残疾日期范围有可能重叠，即在一个记录中禁用1月5日至1月8日，在另一个记录中禁用1月7日至1月10日 - 因此简单的金额将在1月7日重复计算。排除这些重叠并获得准确计数的最佳方法是什么。

Declare @disableranges table (disableFrom datetime, disableTo datetime)
insert into @disableranges
select '01/05/2013', '01/08/2013' union
select '01/07/2013', '01/10/2013' union
select '01/15/2013', '01/20/2013'

declare @fromDate datetime = '01/01/2013'
declare @toDate datetime = '01/31/2013'

declare @totalDays int = DATEDIFF(day,@fromDate,@toDate)
declare @disabledDays int = (0 /*not sure best way to calc this*/)

select @totalDays - @disabledDays

Answer 1

就我而言，试过这个并且工作正常。

Declare @disableranges table (disableFrom datetime, disableTo datetime)
insert into @disableranges
select '01/05/2013', '01/08/2013' union
select '01/07/2013', '01/10/2013' union
select '01/15/2013', '01/20/2013'

declare @fromDate datetime = '01/01/2013'
declare @toDate datetime = '01/31/2013'

declare @totalDays int = DATEDIFF(day,@fromDate,@toDate) + 1 /*Without +1 it is giving 30 instead of 31*/
declare @disabledDays int = (0 /*not sure best way to calc this*/)
/*Fill temporary table with the given date range.*/
SELECT  DATEADD(DAY, nbr - 1, @fromDate) TempDate INTO #Temp
FROM    ( SELECT    ROW_NUMBER() OVER ( ORDER BY c.object_id ) AS Nbr
          FROM      sys.columns c
        ) nbrs
WHERE   nbr - 1 <= DATEDIFF(DAY, @fromDate, @toDate)
/*Check how many dates exists in the disableranges table*/
SELECT @disabledDays=count(*) from #Temp t WHERE 
EXISTS(SELECT * FROM @disableranges 
WHERE t.TempDate BETWEEN disableFrom AND DATEADD(d, -1, disableTo))

select @totalDays /*Output:31*/
select @disabledDays /*Output:10*/
select @totalDays - @disabledDays /*Output:21*/
drop table #Temp

从答案https://stackoverflow.com/a/7825036/341117中获取帮助以填写日期范围

的表格

Answer 2

您可以使用recursive CTE生成@dateFrom和@dateTo之间的日期。然后将日期与范围进行比较，并查找任何范围内的所有日期。最后，计算结果中的行数以获取禁用日期的计数（DEMO）：

-- recursive CTE to generate dates
;with dates as (
  select @fromDate as date
  union all
  select dateadd(day, 1, date)
  from dates
  where date < @toDate
)

-- join with disable ranges to find dates in any range
, disabledDates as (
  select date from dates D
  left join @disableranges R
    on D.date >= R.disableFrom and d.Date < R.disableTo
  group by date
  having count(R.disablefrom) >= 1
)

-- count up the total disabled dates
select @disabledDays=count(*) from disabledDates;

计算日期范围内的天数以及可能重叠的排除项集

2 个答案: