Question

我知道这应该很简单，但我是ruby，haml和rails的新手。

我想显示特定律师的位置列表。我想将它们转换成'to_sentence'，所以除了最后一个位置之外的每个位置都有逗号。

这就是我在show.html.haml视图中的内容。

%ul
- @lawyers.each do |lawyer|
  - if lawyer == @lawyer
    %li.active
      %article
        %h3= lawyer.full_name
        - unless lawyer.phone.nil?
          .phone== Direct #{lawyer.phone}
        .email
          = mail_to lawyer.email, lawyer.email
        - unless @lawyer.office_locations.empty?
          - if @lawyer.office_locations.count > 1
            .locations_list
              %ul
                %li Locations:
                - @lawyer.office_locations.each do |office_location|
                  %li.locations== #{office_location.city}
          - else
            .locations_list
              %ul
                %li Location:
                - lawyer.office_locations.each do |office_location|
                  %li== #{office_location.city}

编辑：这就是我的尝试。

        - unless @lawyer.office_locations.empty?
          - if @lawyer.office_locations.count > 1
            .locations_list
              %ul
                %li Locations:
                %li== lawyer.office_locations.collect{ |p| "#{p.office_locations.city}"}.to_sentence

我不知道它是否有所不同，但lawyer和office_location是两个单独的模型，它们都是HABTM。

我知道这是错误的做法，但我似乎无法让to_sentece或.pluralize工作。我尝试使用这篇文章中的答案Ruby on Rails seems to be auto-escaping html created by link_to，但我无法使其发挥作用。

我假设我可能想把这个逻辑放在帮助器里？任何帮助将不胜感激。

Answer 1

这一行有一个问题：

%li== lawyer.office_locations.collect{ |p| "#{p.office_locations.city}"}.to_sentence

您正在.office_locations关系中的每个p上致电lawyer.office_locations。我怀疑你想要阻止{ |p| "#{p.city}"}。

如果要复数“Location / s”，可以使用参数调用pluralize方法： "Location".pluralize(1)将返回“位置”，并且 "Location".pluralize(2)（或大于1的任何内容）将返回“地点”。因此，您可以将其添加到模板中：

%li= "Location".pluralize(lawyer.office_locations.count)

使用to_sentence与HAML和mongoid

1 个答案: