您好Html表单发送0而不是1到我的数据库有问题,它被设置为tinyint 1 我已经搞砸了好几天了。
我使用phpmyadmin xampp服务器html php
<!--THIS IS SKILLS-->
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
if (!isset($_POST['action']))
mysql_select_db("client", $con);
$sql="INSERT INTO skills (driving_licence,HGV,engineer,carpenter,chef,PSV)
VALUES
('$_POST[driving_licence]','$_POST[HGV]','$_POST[engineer]','$_POST[carpenter]','$_POST[chef]','$_POST[PSV]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "skills have been added";
mysql_close($con);
?>
表单代码是
<center><form method="post" action="skills.php">
<table cellspacing="50">
<tr>
<center><h1>Record Client Skills</h1></center>
<center><p> Please choose the relevent boxes</p></center>
<center><input type="checkbox" name="driving_licence" value="driving_licence">I have a Full UK Driving Licence<br>
<input type="checkbox" name="hdv" value="hgv">I hold a valid a HGV licence<br>
<input type="checkbox" name="engineer" value="engineer">I have an Engineering qualification <br>
<input type="checkbox" name="carpenter" value="carpenter">I have a Carpentry qualification <br>
<input type="checkbox" name="chef" value="chef">I have Catering qualification<br>
<input type="checkbox" name="psv licence" value="psv">I have a valid PSV licence<br>
</tr>
</table>
<input type="reset" value="Reset Form"/> <input type="submit" value="Send" />
</center>
有人可以帮忙吗?
罗布
答案 0 :(得分:0)
设置复选框value="1"
,否则字符串"driving_license"
将传递到您的db-field tinyint
: - (
AND:移至mysqli或PDO,不推荐使用mysql。
答案 1 :(得分:0)
并且最好使用bit(1)
代替tinyint
作为布尔值,不要使用root连接到mysql并使用PDO或Mysqli,最后打印mysql错误不是好办法您的用户,使用php数据库类之一
答案 2 :(得分:0)
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
if (isset($_POST['submit']))
{
mysql_select_db("client", $con);
$sql="INSERT INTO skills (driving_licence,HGV,engineer,carpenter,chef,PSV)
VALUES
('$_POST[driving_licence]','$_POST[HGV]','$_POST[engineer]','$_POST[carpenter]','$_POST[chef]','$_POST[PSV]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "skills have been added";
mysql_close($con);
}
?>
你的Html表格 -
<center><form method="post" name="f1" action="skills.php">
<table cellspacing="50">
<tr>
<center><h1>Record Client Skills</h1></center>
<center><p> Please choose the relevent boxes</p></center>
<center><input type="checkbox" name="driving_licence" value="driving_licence">I have a Full UK Driving Licence<br>
<input type="checkbox" name="hdv" value="hgv">I hold a valid a HGV licence<br>
<input type="checkbox" name="engineer" value="engineer">I have an Engineering qualification <br>
<input type="checkbox" name="carpenter" value="carpenter">I have a Carpentry qualification <br>
<input type="checkbox" name="chef" value="chef">I have Catering qualification<br>
<input type="checkbox" name="psv licence" value="psv">I have a valid PSV licence<br>
</tr>
</table>
<input type="reset" value="Reset Form"/> <input type="submit" value="Send" name="submit" />
</center>