Doctrine连接查询以使所有记录满足大于1的计数

时间:2013-03-04 07:37:52

标签: doctrine-orm createquery

我试过正常的sql查询

SELECT activity_shares.id FROM `activity_shares` 
INNER JOIN (SELECT `activity_id` FROM `activity_shares`
GROUP BY `activity_id`
HAVING  COUNT(`activity_id`) > 1 ) dup ON activity_shares.activity_id = dup.activity_id

这给了我记录ID 10 11

但是我试图在Doctrine query builder中执行相同的查询,

 $qb3=$this->getEntityManager()->createQueryBuilder('c')
           ->add('select','c.id')
           ->add('from','MyBundleDataBundle:ActivityShare c')
           ->innerJoin('c.activity', 'ca')
         //  ->andWhere('ca.id = c.activity')
           ->groupBy('ca.id')
          ->having('count(ca.id)>1');

编辑:

        $query3=$qb3->getQuery();
        $query3->getResult();

生成的SQL是:

SELECT a0_.id AS id0 FROM activity_shares a0_ 
INNER JOIN activities a1_ ON a0_.activity_id = a1_.id 
GROUP BY a1_.id HAVING count(a1_.id) > 1

只提供1条 10 的记录。我想得到两者。我不知道我哪里出错了。有什么想法吗?

我的表结构是:

ActivityShare
    +-----+---------+-----+---
    | Id  |activity |Share| etc...
    +-----+---------+-----+----
    | 1   | 1       |1    |
    +-----+---------+-----+---
    | 2   | 1       | 2   |
    +-----+---------+-----+---

ActivityActivity表的外键。 我想得到Id的1和2

2 个答案:

答案 0 :(得分:0)

简化的SQL

首先让我简化该查询,以便得到相同的结果:

SELECT id FROM `activity_shares` 
GROUP BY `id`
HAVING  COUNT(`activity_id`) > 1 

Docrtrine QueryBuilder

如果你在表中存储了activty的id,就像你建议的那样:

您可以使用简化的SQL构建查询:

$results =$this->getEntityManager()->createQueryBuilder('c')
           ->add('select','c.id')
           ->add('from','MyBundleDataBundle:ActivityShare c')
           ->groupBy('c.id')
           ->having('count(c.activity)>1');
           ->getResult();

如果您正在使用关联表(Doctrine logic)

在这里你必须使用连接,但计数可能很棘手

解决方案1 ​​

像使用权限一样使用关联表(因为我看到你只需要id) 假设表名是activityshare_activity

它将有两个字段activity_id和activityshare_id,如果您找到一种方法将新列ID添加到该表并使其自动增量+主要,其余的很容易:

新实体名为 ActivityShareActivity

$results =$this->getEntityManager()->createQueryBuilder('c')
           ->add('select','c.activityshare_id')
           ->add('from','MyBundleDataBundle:ActivityShareActivity c')
           ->groupBy('c.activityshare_id')
           ->having('count(c.activity_id)>1');
           ->getResult();

添加新标识列以使其与教义兼容的步骤(您需要执行一次):

  1. 添加列(INT,NOT NULL)不要自动增量

    ALTER TABLE tableName ADD id INT NOT NULL

  2. 使用类似于

  3. 的php循环填充列
  4. 将列修改为自动增量

    ALTER TABLE tableName MODIFY id INT NOT NULL AUTO_INCREMENT

  5. <强>溶液2

    对查询的更正

    $result=$this->getEntityManager()->createQueryBuilder()
               ->select('c.id')
               ->from('MyBundleDataBundle:ActivityShare', 'c')
               ->innerJoin('c.activity', 'ca')
               ->groupBy('c.id') //note: it's c.id not ca.id
               ->having('count(ca.id)>1')
               ->getResult();
    

    我最后发布了这个,因为我不是100%确定有+计数的输出,但它应该说得很好:)

答案 1 :(得分:0)

感谢您的回答。我终于得到了答案

我的学说查询是:

$subquery=$this->getEntityManager()->createQueryBuilder('as')
      ->add('select','a.id')
      ->add('from','MyBundleDataBundle:ActivityShare as')
      ->innerJoin('as.activity', 'a')
      ->groupBy('a.id')
      ->having('count(a.id)>1');



 $query=$this->getEntityManager()->createQueryBuilder('c')
      ->add('select','c.id')
      ->add('from','ChowzterDataBundle:ActivityShare c')
      ->innerJoin('c.activity', 'ca');

    $query->andWhere($query->expr()->in('ca.id', $subquery->getDql()))
      ;

    $result = $query->getQuery();
    print_r($result->getResult());

SQL看起来像:

SELECT a0_.id AS id0 FROM activity_shares a0_ INNER JOIN activities a1_ ON a0_.activity_id = a1_.id WHERE a1_.id IN (SELECT a2_.id FROM activity_shares a3_ INNER JOIN activities a2_ ON a3_.activity_id = a2_.id GROUP BY a2_.id HAVING count(a2_.id) > 1