对于这项任务,我们需要让一个人输入人数和年数。然后程序从数组中获取随机数,然后给出一堆不同的信息。到目前为止我设法做到的是:
import java.util.Scanner;
import java.util.Random;
public class InternSalary {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner s = new Scanner (System.in);
Random myRandom = new Random();
int value = myRandom.nextInt(19000) + 1000;
int years = 0;
int people = 0;
int total = 0;
int average = 0;
System.out.println("Enter number of people for which you have salary information");
people = s.nextInt();
System.out.println("Enter number of years for which you have salary information");
years = s.nextInt();
int [][] salaries = new int [people][years];
for (int i=0; i<people; i++) {
for (int j=0; j <years; j++)
salaries[i][j] = myRandom.nextInt (19000)+1000;
}
for (int i = 0; i < people; i++) {
total = 0;
for(int j = 0; j < years; j++) {
total += salaries[i][j];
}
System.out.println(total/years);
System.out.println(total);
}
}
}
这给出了每年制作一个人的平均值,然后是他们制作的总数。它仍然没有格式化,但我会稍后再这样做。我无法弄清楚的是如何输出每个人每年制作多少钱,这些数字加在一起以获得一个人的总金额。任何帮助将不胜感激
答案 0 :(得分:0)
在此部分中,您需要打印出每个薪水。 如果你考虑一下,你就把每年的工资加到总数中。那么为什么不用你需要的任何格式打印出来。
for(int j = 0; j < years; j++) {
total += salaries[i][j];
//add this line
System.out.println(salaries[i][j]);
}