Question

从字面上看，我被问到这个问题“”Fibonacci序列是0,1,1,2,3,5,8,13 ......;前两个项是0和1，其后的每个项是前两个项的和 - 即Fib [n] = Fib [n - 1] + Fib [n - 2]。使用此信息，编写一个C ++程序，计算Fibonacci序列中的第n个数字，用户以交互方式在程序中输入n。例如，如果n = 6，程序应显示值8.“

感谢上一个问题的答案，我已将其放入我的完整代码中。我确实有一个循环，这意味着用户可以选择是否继续该程序。它工作得更早，但现在没有任何反应。任何人都可以对此有所了解吗？谢谢

{int N;

char ans = 'C';

while (toupper(ans) == 'C')
{
    cout<<"This program is designed to give the user any value of the Fibonacci Sequence that they desire, provided the number is a positive integer.";//Tell user what the program does

    cout<<"\n\nThe formula of the Fibonacci Sequence is;   Fib[N] = Fib[N – 1] + Fib[N – 2]\n\n"; //Declare the Formula for the User

    cout<<"Enter a value for N, then press Enter:"; //Declare Value that the User wants to see

    cin>>N;//Enter the Number

    if (N>1) {
            long u = 0, v = 1, t;

            for(int Variable=2; Variable<=N; Variable++)
            {
                t = u + v;
                u = v;
                v = t;
            } //Calculate the Answer

        cout<<"\n\nThe "<<N<<"th Number of the Fibonacci Sequence is: "<<t; //Show the Answer
    }

    if (N<0) {
        cout<<"\n\nThe value N must be a POSITIVE integer, i.e. N > 0"; //Confirm that N must be a positive integer. Loop.
    }
    if (N>100) {
        cout<<"\n\nThe value for N must be less than 100, i.e. N < 100. N must be between 0 - 100.";//Confirm that N must be less than 100. Loop.
    }
    if (N==0) {
        cout<<"\n\nFor your value of N, \nFib[0] = 0"; //Value will remain constant throughout, cannot be caculated through formula. Loop.
    }
    if (N==1) {
        cout<<"\n\nFor your value of N. \nFib[1]=1";//Value will remain constant throughout, cannot be caculated through formula. Loop.
    }

  cout << "\n\nIf you want to select a new value for N, then click C then press Enter. If you want to quit, click P then press Enter: ";
    cin >> ans;
}


return 0;

}

Answer 1

所有你需要的是在cout下面放两行。而且你不需要额外的{}，但它不会造成伤害。

Answer 2

这是你的主要循环：

for(int i=2; i<=N; i++)
{
    t = u + v;
    u = v;
    v = t;

    cout<<t<<"is your answer";
}

很明显，它会在循环中的每一次传递中打印出你的答案。

只需将打印件移到循环外部...完成所有计算后，您只需看一次打印：

for(int i=2; i<=N; i++)
{
    t = u + v;
    u = v;
    v = t;
}
cout<<t<<"is your answer";

我在您的代码中看到的其他问题：

您声明了一个函数：

unsigned long long Fib(int N);

但它从未被定义或使用过。为什么这个声明在这里？（删除它）

你有一套冗余的大括号：

else {
        {
            unsigned long long u = 0, v = [....]

你不需要紧跟牙箍，然后再戴上牙套。

Fibonacci Sequence C ++显示一个/最大值

2 个答案: