我有这个xml文件
<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<bookstore>
<book category="COOKING">
<title lang="en">Everyday Italian</title>
<author>Giada De Laurentiis</author>
<year>2005</year>
<price>30.00</price>
</book>
<book category="CHILDREN">
<title lang="en">Harry Potter</title>
<author>J K. Rowling</author>
<year>2005</year>
<price>29.99</price>
</book>
<book category="WEB">
<title lang="en">XQuery Kick Start</title>
<author>James McGovern</author>
<author>Per Bothner</author>
<author>Kurt Cagle</author>
<author>James Linn</author>
<author>Vaidyanathan Nagarajan</author>
<year>2003</year>
<price>49.99</price>
</book>
<book category="WEB">
<title lang="en">Learning XML</title>
<author>Erik T. Ray</author>
<year>2003</year>
<price>39.95</price>
</book>
</bookstore>
我有这个PHP代码
<?php
$xslDoc = new DOMDocument();
$xslDoc->load("test.xsl");
$xmlDoc = new DOMDocument();
$xmlDoc->load("test.xml");
$xsltProcessor = new XSLTProcessor();
$xsltProcessor->registerPHPFunctions();
$xsltProcessor->importStyleSheet($xslDoc);
$xsltProcessor->setParameter('','s_name', 'title');
$xsltProcessor->setParameter('','s_value', 35);
echo $xsltProcessor->transformToXML($xmlDoc);
?>
这是我的XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:php="http://php.net/xsl" xmlns:str="http://exslt.org/strings" exclude-result-prefixes="str">
<xsl:template match="/">
<html>
<body>
<table border="1">
<tr bgcolor="#9acd32">
<th>O/p</th>
</tr>
<xsl:for-each select="/bookstore/book[price>$s_value]/$s_name">
<tr>
<td><xsl:value-of select="."/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
这里我想向我的xsl转换发送一些参数。这是s_name
和s_value
这给了我错误
如果我只使用s_value
那么它的工作正常n xsl将是
<xsl:for-each select="/bookstore/book[price>$s_value]/title">
如果我使用它们那么它不起作用
答案 0 :(得分:2)
这是无效的XPath:
/bookstore/book[price>$s_value]/$s_name
因为在像这样的斜杠之后不能发生变量。为了完成你想要做的事,试试这个:
/bookstore/book[price>$s_value]/*[local-name() = $s_name]