我正在寻找一种工具，它将批量添加许可证标题到某些源文件，其中一些已经有标题。是否有一个工具可以插入标题，如果它尚不存在？
编辑：我故意没有标记这个问题的答案，因为答案基本上都是环境特定的和主观的
答案 0 :(得分：58)
#!/bin/bash
for i in *.cc # or whatever other pattern...
do
if ! grep -q Copyright $i
then
cat copyright.txt $i >$i.new && mv $i.new $i
fi
done
答案 1 :(得分：15)
Python解决方案，根据您自己的需要进行修改
特点：
-
# updates the copyright information for all .cs files
# usage: call recursive_traversal, with the following parameters
# parent directory, old copyright text content, new copyright text content
import os
excludedir = ["..\\Lib"]
def update_source(filename, oldcopyright, copyright):
utfstr = chr(0xef)+chr(0xbb)+chr(0xbf)
fdata = file(filename,"r+").read()
isUTF = False
if (fdata.startswith(utfstr)):
isUTF = True
fdata = fdata[3:]
if (oldcopyright != None):
if (fdata.startswith(oldcopyright)):
fdata = fdata[len(oldcopyright):]
if not (fdata.startswith(copyright)):
print "updating "+filename
fdata = copyright + fdata
if (isUTF):
file(filename,"w").write(utfstr+fdata)
else:
file(filename,"w").write(fdata)
def recursive_traversal(dir, oldcopyright, copyright):
global excludedir
fns = os.listdir(dir)
print "listing "+dir
for fn in fns:
fullfn = os.path.join(dir,fn)
if (fullfn in excludedir):
continue
if (os.path.isdir(fullfn)):
recursive_traversal(fullfn, oldcopyright, copyright)
else:
if (fullfn.endswith(".cs")):
update_source(fullfn, oldcopyright, copyright)
oldcright = file("oldcr.txt","r+").read()
cright = file("copyrightText.txt","r+").read()
recursive_traversal("..", oldcright, cright)
exit()
答案 2 :(得分：15)
查看copyright-header RubyGem。它支持扩展名以php，c，h，cpp，hpp，hh，rb，css，js，html结尾的文件。它还可以添加和删除标题。
输入“sudo gem install copyright-header”
之后，可以执行以下操作：
copyright-header --license GPL3 \
--add-path lib/ \
--copyright-holder 'Dude1 <dude1@host.com>' \
--copyright-holder 'Dude2 <dude2@host.com>' \
--copyright-software 'Super Duper' \
--copyright-software-description "A program that makes life easier" \
--copyright-year 2012 \
--copyright-year 2012 \
--word-wrap 80 --output-dir ./
它还支持使用--license-file参数的自定义许可证文件。
答案 3 :(得分：14)
这是一个Bash脚本，只要文件license.txt中有许可证头，就可以解决这个问题：
文件addlicense.sh：
#!/bin/bash
for x in $*; do
head -$LICENSELEN $x | diff license.txt - || ( ( cat license.txt; echo; cat $x) > /tmp/file;
mv /tmp/file $x )
done
现在在您的源目录中运行它：
export LICENSELEN=`wc -l license.txt | cut -f1 -d ' '`
find . -type f \(-name \*.cpp -o -name \*.h \) -print0 | xargs -0 ./addlicense.sh
答案 4 :(得分：12)
编辑： 如果你正在使用eclipse，那就是a plugin
我根据Silver Dragon的回复写了一个简单的python脚本。 我需要一个更灵活的解决方案，所以我想出了这个。 它允许您以递归方式将头文件添加到目录中的所有文件。 您可以选择添加文件名应匹配的正则表达式，以及目录名称应匹配的正则表达式以及文件中第一行不匹配的正则表达式。 您可以使用最后一个参数来检查标头是否已包含在内。
如果以shebang（＃！）开头，此脚本将自动跳过文件的第一行。这不会破坏依赖于此的其他脚本。 如果您不希望出现这种情况，则必须在writeheader中注释掉3行。
这里是：
#!/usr/bin/python
"""
This script attempts to add a header to each file in the given directory
The header will be put the line after a Shebang (#!) if present.
If a line starting with a regular expression 'skip' is present as first line or after the shebang it will ignore that file.
If filename is given only files matchign the filename regex will be considered for adding the license to,
by default this is '*'
usage: python addheader.py headerfile directory [filenameregex [dirregex [skip regex]]]
easy example: add header to all files in this directory:
python addheader.py licenseheader.txt .
harder example adding someone as copyrightholder to all python files in a source directory,exept directories named 'includes' where he isn't added yet:
python addheader.py licenseheader.txt src/ ".*\.py" "^((?!includes).)*$" "#Copyright .* Jens Timmerman*"
where licenseheader.txt contains '#Copyright 2012 Jens Timmerman'
"""
import os
import re
import sys
def writeheader(filename,header,skip=None):
"""
write a header to filename,
skip files where first line after optional shebang matches the skip regex
filename should be the name of the file to write to
header should be a list of strings
skip should be a regex
"""
f = open(filename,"r")
inpt =f.readlines()
f.close()
output = []
#comment out the next 3 lines if you don't wish to preserve shebangs
if len(inpt) > 0 and inpt[0].startswith("#!"):
output.append(inpt[0])
inpt = inpt[1:]
if skip and skip.match(inpt[0]): #skip matches, so skip this file
return
output.extend(header) #add the header
for line in inpt:
output.append(line)
try:
f = open(filename,'w')
f.writelines(output)
f.close()
print "added header to %s" %filename
except IOError,err:
print "something went wrong trying to add header to %s: %s" % (filename,err)
def addheader(directory,header,skipreg,filenamereg,dirregex):
"""
recursively adds a header to all files in a dir
arguments: see module docstring
"""
listing = os.listdir(directory)
print "listing: %s " %listing
#for each file/dir in this dir
for i in listing:
#get the full name, this way subsubdirs with the same name don't get ignored
fullfn = os.path.join(directory,i)
if os.path.isdir(fullfn): #if dir, recursively go in
if (dirregex.match(fullfn)):
print "going into %s" % fullfn
addheader(fullfn, header,skipreg,filenamereg,dirregex)
else:
if (filenamereg.match(fullfn)): #if file matches file regex, write the header
writeheader(fullfn, header,skipreg)
def main(arguments=sys.argv):
"""
main function: parses arguments and calls addheader
"""
##argument parsing
if len(arguments) > 6 or len(arguments) < 3:
sys.stderr.write("Usage: %s headerfile directory [filenameregex [dirregex [skip regex]]]\n" \
"Hint: '.*' is a catch all regex\nHint:'^((?!regexp).)*$' negates a regex\n"%sys.argv[0])
sys.exit(1)
skipreg = None
fileregex = ".*"
dirregex = ".*"
if len(arguments) > 5:
skipreg = re.compile(arguments[5])
if len(arguments) > 3:
fileregex = arguments[3]
if len(arguments) > 4:
dirregex = arguments[4]
#compile regex
fileregex = re.compile(fileregex)
dirregex = re.compile(dirregex)
#read in the headerfile just once
headerfile = open(arguments[1])
header = headerfile.readlines()
headerfile.close()
addheader(arguments[2],header,skipreg,fileregex,dirregex)
#call the main method
main()
答案 5 :(得分：10)
对于Java，http://code.google.com/p/maven-license-plugin/
亲切的问候
答案 6 :(得分：10)
这里有一个简单的仅限Windows的UI工具，可以在文件夹中搜索指定类型的所有文件，将您想要的文本添加到顶部（许可文本），并将结果复制到另一个目录（避免潜在的覆盖问题）。它也是免费的。必需.Net 4.0。
我实际上是作者，所以请随时请求修复或新功能......但是在交付时间表上没有承诺。 ;）
答案 7 :(得分：4)
签出许可证加法器。它支持多个代码文件（甚至是自定义代码文件）并正确处理现有标头。已经有最常见的开源许可证模板。
答案 8 :(得分：2)
Here's one我在Apache列表中找到了。它用Ruby编写，看起来很容易阅读。你甚至可以用rake调用它来获得额外的特别好处。 ：）
答案 9 :(得分：2)
这是我在PHP中用来修改PHP文件的一个。我还有旧的许可证信息要删除，所以它先替换旧文本，然后在打开后立即添加新文本
<?php
class Licenses
{
protected $paths = array();
protected $oldTxt = '/**
* Old license to delete
*/';
protected $newTxt = '/**
* @license http://opensource.org/licenses/osl-3.0.php Open Software License (OSL 3.0)
*/';
function licensesForDir($path)
{
foreach(glob($path.'/*') as $eachPath)
{
if(is_dir($eachPath))
{
$this->licensesForDir($eachPath);
}
if(preg_match('#\.php#',$eachPath))
{
$this->paths[] = $eachPath;
}
}
}
function exec()
{
$this->licensesForDir('.');
foreach($this->paths as $path)
{
$this->handleFile($path);
}
}
function handleFile($path)
{
$source = file_get_contents($path);
$source = str_replace($this->oldTxt, '', $source);
$source = preg_replace('#\<\?php#',"<?php\n".$this->newTxt,$source,1);
file_put_contents($path,$source);
echo $path."\n";
}
}
$licenses = new Licenses;
$licenses->exec();
答案 10 :(得分：1)
如果你还需要一个，我写了一个小工具，名为 SrcHead 。您可以在http://www.solvasoft.nl/downloads.html
找到它答案 11 :(得分：0)
如果您使用的是sbt，则有https://github.com/Banno/sbt-license-plugin