Question

我有这样的数据，这是在远程网址上：

{
   "data": [
      {
         "id": "1234567890",
         "name": "data_name",
         "period": "data_period",
         "values": [
            {
               "value": 52,
               "end_time": "2013-01-21T08:00:00+0000"
            },
            {
               "value": 54,
               "end_time": "2013-01-22T08:00:00+0000"
            },
            {
               "value": 57,
               "end_time": "2013-01-23T08:00:00+0000"
            },
            {
               "value": 58,
               "end_time": "2013-01-24T08:00:00+0000"
            }
      ],
         "title": "Some title",
         "description": "Some description"
      }
   ]
}

有没有办法从链接到php变量？我对PHP有很好的了解，但我的javascript知识非常糟糕，所以我不知道如何实现这一点。从这一切来看，我实际上只需要“值”和“end_time”变量。

Answer 1

此处不需要JavaScript。这是JSON表示法，PHP可以使用标准函数轻松解析。

试试这个：

$contents = file_get_contents($url); // You can also use cURL here if you like
$obj = json_decode($contents);

然后您可以将$var视为对象。例如，$obj->data[0]->values会返回包含value和end_time字段的对象数组：

Array
(
    [0] => stdClass Object
        (
            [value] => 52
            [end_time] => 2013-01-21T08:00:00+0000
        )

    [1] => stdClass Object
        (
            [value] => 54
            [end_time] => 2013-01-22T08:00:00+0000
        )

    [2] => stdClass Object
        (
            [value] => 57
            [end_time] => 2013-01-23T08:00:00+0000
        )

    [3] => stdClass Object
        (
            [value] => 58
            [end_time] => 2013-01-24T08:00:00+0000
        )

)

有没有办法从URL获取facebook见解数据并将其放入php变量？

1 个答案: