我有这个函数,在调用它时会返回三个值。
function GetCashierDetail ($UserID){
$GetCashierID = "SELECT cashiers_CashierID,cashiers_Total,cashiers_Last_Total
FROM `cashiers`
WHERE `cashiers_CashierCloseDate` is null and `cashiers_Status`='0'
and `cashiers_Delete` = '0' and `cashiers_User` = '".$UserID."'";
$objQueryCashierID = mysql_query($GetCashierID) or die ("Error Query [".$strSQL."]");
$GetCashierIDResult = mysql_fetch_array($objQueryCashierID);
$BillsCashierID = $GetCashierIDResult['cashiers_CashierID'];
$CashierTotal=$GetCashierIDResult['cashiers_Total'];
$CashierLastTotal=$GetCashierIDResult['cashiers_Last_Total'];
$num=mysql_affected_rows();
// Return Data
return $cashier_data = array('cashierId'=>$BillsCashierID ,
'CashierTotal'=>$CashierTotal ,
'CashierLastTotal'=>$CashierLastTotal );
}
现在调用此函数时GetCashierDetail (11)
我需要在这个变量上打印$cashier_data
$ID = $BillsCashierID
以其他方式使用它。
我会尝试
class Bills {
// Get Cashier ID
function GetCashierDetail ($ausers_ID){
$GetCashierID = "SELECT cashiers_CashierID,cashiers_Total,cashiers_Last_Total
FROM `cashiers`
WHERE `cashiers_CashierCloseDate` is null and `cashiers_Status`='0'
and `cashiers_Delete` = '0' and `cashiers_User` = '".$UserID."'";
$objQueryCashierID = mysql_query($GetCashierID) or die ("Error Query [".$strSQL."]");
$GetCashierIDResult = mysql_fetch_array($objQueryCashierID);
$BillsCashierID = $GetCashierIDResult['cashiers_CashierID'];
$CashierTotal=$GetCashierIDResult['cashiers_Total'];
$CashierLastTotal=$GetCashierIDResult['cashiers_Last_Total'];
$num=mysql_affected_rows();
// Return Data
return $cashier_data = array('cashierId'=>$BillsCashierID ,
'CashierTotal'=>$CashierTotal ,
'CashierLastTotal'=>$CashierLastTotal);
}
}
$BillDraftSubmit = new Bills();
$data=$BillDraftSubmit->GetCashierDetail(71);
$cashierId=$data["cashierId"];
$CashierTotal=$data["CashierTotal"];
$CashierLastTotal=$data["CashierLastTotal"];
echo "cashierId".$cashierId;
echo "<br>CashierTotal".$CashierTotal;
echo "<br>CashierLastTotal".$CashierLastTotal;
但我无法得到结果
答案 0 :(得分:2)
怎么样:
$arr = GetCashierDetail (11);
extract($arr);
print $cashierId." ".$CashierTotal." ".$CashierLastTotal;
答案 1 :(得分:1)
$return = GetCashierDetail(11);
$id = $return['cashierId'];
答案 2 :(得分:0)
只返回数组,无需将其分配给任何内容。即。
return array('cashierId'=>$BillsCashierID ,
'CashierTotal'=>$CashierTotal ,
'CashierLastTotal'=>$CashierLastTotal );
或做
$cashier_data = array('cashierId'=>$BillsCashierID ,
'CashierTotal'=>$CashierTotal ,
'CashierLastTotal'=>$CashierLastTotal );
return $cashier_data;
然后当您使用$cd = GetCashierDetail(1);
返回时,您可以访问$cd['CashierTotal']
答案 3 :(得分:0)
为什么不返回一个数组?
function GetCashierDetail ($UserID){
$GetCashierID = "SELECT cashiers_CashierID,cashiers_Total,cashiers_Last_Total
FROM `cashiers`
WHERE `cashiers_CashierCloseDate` is null and `cashiers_Status`='0'
and `cashiers_Delete` = '0' and `cashiers_User` = '".$UserID."'";
$objQueryCashierID = mysql_query($GetCashierID) or die ("Error Query [".$strSQL."]");
$GetCashierIDResult = mysql_fetch_array($objQueryCashierID);
$BillsCashierID = $GetCashierIDResult['cashiers_CashierID'];
$CashierTotal=$GetCashierIDResult['cashiers_Total'];
$CashierLastTotal=$GetCashierIDResult['cashiers_Last_Total'];
$num=mysql_affected_rows();
// Return Data
return array('cashierId'=>$BillsCashierID ,
'CashierTotal'=>$CashierTotal ,
'CashierLastTotal'=>$CashierLastTotal );
}
$user = GetCashierDetail($id);
$ID = $user['cashierId'];
echo $ID;
答案 4 :(得分:0)
//$UserID - your user's id
$result = GetCashierDetail ($UserID);
//now just using as normal array, for example
echo $result['cashierId'];
答案 5 :(得分:0)
如果我正确理解了您的问题,您希望显示收银员ID的值。
你可以这样做..
$cashierData = GetCashierDetail(11);
$ID = $cashierData['cashierId'];
echo 'cashier ID is: ' . $ID;
同样,您也可以通过$cashierData['CashierTotal']
获得CashierTotal,依此类推
答案 6 :(得分:0)
我不确定我是否把你弄好了......
list($id,,) = GetCashierDetail(11);
echo $id;