Question

我需要在mysql表中计算2个不同字段的某些值，如果可能，最好使用一个查询。

 Number     Answer
 0          Y
 0          N
 1          Y
 2          Y
 0          Y

我需要知道该领域有多少＆＃39; Number＆＃39;值为0.

我还需要了解该领域有多少人回答＆＃39;的值为N.

你能帮我构建查询吗，还有PHP把它们变成一个变量供使用吗？

即

 echo "There are ".$number." entries in the number field with a value of 0";
 echo "There are ".$answer." entries in the answer field with a value of N";

感谢您的帮助，在我甚至可以继续使用php之前，我一直试图找出mysql计数。

Answer 1

您可以使用带有CASE表达式的聚合函数在单个查询中执行此操作：

select 
  sum(case when number=0 then 1 else 0 end) TotalNumber,
  sum(case when answer='N' then 1 else 0 end) TotalAnswer
from yourtable

请参阅SQL Fiddle with Demo

要通过PHP获取这些结果，您可以使用mysqli_或PDO API：

<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");

/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

$query = "SELECT Sum(CASE 
             WHEN number = 0 THEN 1 
             ELSE 0 
           end) TotalNumber, 
       Sum(CASE 
             WHEN answer = 'N' THEN 1 
             ELSE 0 
           end) TotalAnswer 
FROM   yourtable";

if ($result = mysqli_query($link, $query)) {

    /* fetch associative array */
    $row = mysqli_fetch_assoc($result);
    echo "There are " . $row['TotalNumber'] . "entries in the number field with a value of 0";
    echo "There are " . $row['TotalAnswer'] . "entries in the answer field with a value of N";

    /* free result set */
    mysqli_free_result($result);
}

/* close connection */
mysqli_close($link);
?>

Answer 2

试试这个：

Select SUM(IF(Number = 0, 1, 0)) as count_numbers,
SUM(IF(Answer = 'N', 1, 0)) as count_answers
From table

Saludos;）

Answer 3

Select count(`Number`) from yourtable where `Number` = 0;
Select count(`Answer`) from yourtable where `Answer` = 'N';

MySQL计算2个字段中的唯一值

3 个答案: