在我的java项目中,我将FileInputStream传递给一个函数, 我需要转换(类型转换FileInputStream到字符串), 怎么做。??
public static void checkfor(FileInputStream fis) {
String a=new String;
a=fis //how to do convert fileInputStream into string
print string here
}
答案 0 :(得分:26)
您无法直接将其转换为字符串。你应该实现这样的东西 将此代码添加到您的方法
//Commented this out because this is not the efficient way to achieve that
//StringBuilder builder = new StringBuilder();
//int ch;
//while((ch = fis.read()) != -1){
// builder.append((char)ch);
//}
//
//System.out.println(builder.toString());
使用Aubin的解决方案:
public static String getFileContent(
FileInputStream fis,
String encoding ) throws IOException
{
try( BufferedReader br =
new BufferedReader( new InputStreamReader(fis, encoding )))
{
StringBuilder sb = new StringBuilder();
String line;
while(( line = br.readLine()) != null ) {
sb.append( line );
sb.append( '\n' );
}
return sb.toString();
}
}
答案 1 :(得分:18)
public static String getFileContent(
FileInputStream fis,
String encoding ) throws IOException
{
try( BufferedReader br =
new BufferedReader( new InputStreamReader(fis, encoding )))
{
StringBuilder sb = new StringBuilder();
String line;
while(( line = br.readLine()) != null ) {
sb.append( line );
sb.append( '\n' );
}
return sb.toString();
}
}
答案 2 :(得分:5)
使用Apache commons IOUtils函数
import org.apache.commons.io.IOUtils;
InputStream inStream = new FileInputStream("filename.txt");
String body = IOUtils.toString(inStream, StandardCharsets.UTF_8.name());
答案 3 :(得分:4)
不要犯错误依赖或不必要地转换/丢失最终字符。逐字逐句地做。不要忘记使用正确的字符编码来插入流。
public String getFileContent( FileInputStream fis ) {
StringBuilder sb = new StringBuilder();
Reader r = new InputStreamReader(fis, "UTF-8"); //or whatever encoding
int ch = r.read();
while(ch >= 0) {
sb.append(ch);
ch = r.read();
}
return sb.toString();
}
如果你想提高效率,你可以使用字符数组,但说实话,循环字符仍然可以很快。
public String getFileContent( FileInputStream fis ) {
StringBuilder sb = new StringBuilder();
Reader r = new InputStreamReader(fis, "UTF-8"); //or whatever encoding
char[] buf = new char[1024];
int amt = r.read(buf);
while(amt > 0) {
sb.append(buf, 0, amt);
amt = r.read(buf);
}
return sb.toString();
}
答案 4 :(得分:1)
使用以下代码---->
try {
FileInputStream fis=new FileInputStream("filename.txt");
int i=0;
while((i = fis.read()) !=-1 ) { // to reach until the laste bytecode -1
System.out.print((char)i); /* For converting each bytecode into character */
}
fis.close();
} catch(Exception ex) {
System.out.println(ex);
}
答案 5 :(得分:0)
根据我编辑here的答案:
static String convertStreamToString(java.io.InputStream is) {
if (is == null) {
return "";
}
java.util.Scanner s = new java.util.Scanner(is);
s.useDelimiter("\\A");
String streamString = s.hasNext() ? s.next() : "";
s.close();
return streamString;
}
这可以避免所有错误并且运行良好。