我有一个MDIChild
表单,名为form1
的普通表单继承自MDIChild
表单和MDIParent
表单,MDIParent
顶部有一个工具栏{000}在该工具栏中有一个新按钮,当我点击新按钮时,它会加载父窗体内工具栏下方的form
Form1
内有TextBox
,当我点击保存按钮时form1
的值
应通过调用其函数
TextBox
中
但问题是我无法访问MessageBox
TextBox
属性??
我的MDIParent表单代码是
Text
我的form1代码是
public partial class MDIParent1 : Form
{
// private int childFormNumber = 0;
MdiClient mdi = null;
string fname;
public MDIParent1()
{
InitializeComponent();
foreach (Control c in this.Controls)
{
if (c is MdiClient)
{
mdi = (MdiClient)c;
break;
}
}
}
private void load_form(object form)
{
foreach (Form f in mdi.MdiChildren)
{
f.Close();
}
if (form == null)
return;
((Form)form).MdiParent = this;
((Form)form).Show();
((Form)form).AutoScroll = true;
fname = ((Form)form).Name;
}
private void newToolStripButton_Click(object sender, EventArgs e)
{
load_form(new Form1());
}
private void saveToolStripButton_Click(object sender, EventArgs e)
{
if (fname == "Form1")
{
Form1 f1 = new Form1();
f1.show_message();
}
}
我的MDIChild表单代码是
public void show_message()
{
MessageBox.Show(textBox1.Text);
}
任何人都可以帮助我吗?
答案 0 :(得分:0)
我理解你正在做些什么来访问MDIChild表单数据。试试这个: -
private void ShowNewForm(object sender, EventArgs e)
{
Form childForm = new Form();
childForm.MdiParent = this;
// childForm.ContextMenuStrip = contextMenuStrip1;
//this.contextMenuStrip1.ResumeLayout(false);
RichTextBox text = new RichTextBox();
text.Dock = DockStyle.Fill;
childForm.Controls.Add(text);
childForm.Text = "Page " + this.MdiChildren.Count();
childForm.Show();
}
private void OpenFile(object sender, EventArgs e)
{
OpenFileDialog openFileDialog = new OpenFileDialog();
openFileDialog.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.Personal);
openFileDialog.Filter = "Text Files (*.txt)|*.txt|All Files (*.*)|*.*";
if (openFileDialog.ShowDialog(this) == DialogResult.OK)
{
string FileName = openFileDialog.FileName;
}
}
private void SaveAsToolStripMenuItem_Click(object sender, EventArgs e)
{
SaveFileDialog saveFileDialog = new SaveFileDialog();
saveFileDialog.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.Personal);
saveFileDialog.Filter = "Text Files (*.txt)|*.txt|All Files (*.*)|*.*";
if (saveFileDialog.ShowDialog(this) == DialogResult.OK)
{
string FileName = saveFileDialog.FileName;
}
}