我是PHP的新手，我这样做了吗？下面的代码的功能将同时将2个值放在数据库中。一旦我在2个文本框中输入值，只有第一个文本框中的值存储在数据库中。如何使用一个表单将这两个值存储到数据库中？
add.php
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("my_database", $con);
mysql_close($con);
?>
<html>
<body>
<form action="insert.php" method="post" name="form1">
Firstname: <input type="text" name="firstname" />
Firstname1: <input type="text" name="firstname" />
Age: <input type="text" name="age" />
<input type="submit" name="form1" />
</form>
</body>
</html>
insert.php
<html>
<head>
<title>Record Added</title>
<meta http-equiv="refresh" content="0;url=select.php">
</head>
<body>
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("my_database", $con);
$sql="INSERT INTO biodata (FirstName)
VALUES
('$_POST[firstname]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "1 record added";
mysql_close($con);
?>
<a href="select.php"> see</a>
</body>
</html>
select.php
<?php
$dbHost = 'localhost';
$dbUser = 'root';
$dbPass = '';
$dbName = 'my_database';
$dbConn = mysql_connect ($dbHost,$dbUser, $dbPass) or die ('MySQL connect failed. ' . mysql_error());
mysql_select_db($dbName) or die('Cannot select database. ' . mysql_error());
?>
<html>
<head>
<title>Display</title>
</head>
<table align="center" border=1>
<tr>
<th> First Name</th>
<th>Last Name </th>
<th> Age </th>
</tr>
<?php
$query = "SELECT * FROM biodata";
$result = mysql_query($query);
while ($row = mysql_fetch_assoc($result)){
?>
<tr><td><?php echo $row['FirstName'];?></td>
</tr>
<?php }?>
</table>
</body>
</html>
答案 0 :(得分：1)
从表单中将您的值作为数组发送，以访问第二个输入。如果没有，您的记录将被覆盖。你不能真正有两个具有相同名称的表单字段，除非它们形成一个数组。这应该是你最好的选择。这里我们将两个值存储在两列的同一个表中。
<form action="add.php" method="post" name="verify">
<font color="#FFFF00">Name:</font> <input type="text" name="FistName[0]" />
<font color="#FFFF00">Name:</font> <input type="text" name="FirstName[1]"/>
<input type="submit" value="add" name="verify"/>
<?php
$names = $_POST["FirstName"];
$FirstName_1 = mysql_real_escape_string($names[0]);
$FirstName_2 = mysql_real_escape_string($names[1]);
$query = "INSERT INTO biodata (FirstName_1, FirstName_2)
VALUES ('" . $FirstName_1 . "', '" . $FirstName_2 . "') ";
$result = mysql_query($query);
?>
<?php
$query = "SELECT * FROM biodata";
$result = mysql_query($query);
while ($row = mysql_fetch_assoc($result)){
?>
<tr><td><?php echo $row["FirstName_1"];?></td>
</tr>
<?php
//Filename: insert.php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql="INSERT INTO Persons (FirstName, LastName, Age)
VALUES
('$_POST[firstname]','$_POST[lastname]','$_POST[age]')";
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error());
}
echo "1 record added";
mysqli_close($con);
?>
您的表格：
<html>
<body>
<form action="insert.php" method="post">
Firstname: <input type="text" name="firstname">
Lastname: <input type="text" name="lastname">
Age: <input type="text" name="age">
<input type="submit">
</form>
</body>
</html>
在这里运行一个简单的课程：