Question

在R i中有2个dataFrames“df1”和“df2”。它们如下：

> df1
   date        value
1  1980-12-10       5
2  1980-12-11       5
3  1980-12-12       5
4  1980-12-13       5
5  1980-12-14       5


>df2
   date        value
1  1980-12-10       15
2  1980-12-11       2
3  1980-12-12       23
4  1980-12-13       44
5  1980-12-14       434
6  1980-12-15       242
7  1980-12-16       22
8  1980-12-17       82
9  1980-12-18       723
10 1980-12-19       72

我想改变“df2”。仅当df1与df2具有相同日期时，df2才必须包含值。其实我需要以下输出：

>df2
   date        value
1  1980-12-10       15
2  1980-12-11       2
3  1980-12-12       23
4  1980-12-13       44
5  1980-12-14       434

是否可以在R？

Answer 1

您可以使用子集和%in%：

df2[df2$date%in%df1$date,]
        date value
1 1980-12-10    15
2 1980-12-11     2
3 1980-12-12    23
4 1980-12-13    44
5 1980-12-14   434

Answer 2

# read in both data frames
df1 <-
    read.table( h = TRUE , text = "date        value
    1980-12-10       5
    1980-12-11       5
    1980-12-12       5
    1980-12-13       5
    1980-12-14       5")

df2 <-
    read.table( h = TRUE , text = "date        value
    1980-12-10       15
    1980-12-11       2
    1980-12-12       23
    1980-12-13       44
    1980-12-14       434
    1980-12-15       242
    1980-12-16       22
    1980-12-17       82
    1980-12-18       723
    1980-12-19       72")

# merge df1 and df2, only keeping the date column from df1
# but note no comma, which maintains the `class` of df1,
# allowing the merge to work appropriately
merge( df1[ 'date' ] , df2 )

# and if you wanted to overwrite df2 with the new results:
df2 <- merge( df1[ 'date' ] , df2 )

Answer 3

您可以使用sqldf来执行SQL INNER JOIN（R合并），例如：

library(sqldf)
sqldf('SELECT df2.*
       FROM df2
       INNER JOIN df1
       ON df1.date = df2.date')
        date value
1 1980-12-10    15
2 1980-12-11     2
3 1980-12-12    23
4 1980-12-13    44
5 1980-12-14   434

比较两个数据帧并改变R中的一个数据帧

3 个答案: