使用json我得到的值,从尝试使用以下脚本舍入值:
function onLoad(){
var output = $('#product');
var id = getUrlVars()["cPath"];
$.ajax({
url: 'getprice.php?cPath='+id,
data : {type : 'product'},
dataType: 'jsonp',
jsonp: 'jsoncallback',
timeout: 5000,
success: function(data){
$.each(data, function(c,prd){
var price =Math.round(prd.products_price,2);
var product = '<span class="normalprice">$' + price + '</span>' ;
output.append(product);
}
});
output.listview("refresh");
//data loaded
},
});
}
// OutPut NEEDS
prd.products_price=450.2500
price=$450.25
也尝试这种格式但不起作用:
1. var num = Math.val(prd.products_price);
var price = num.toFixed(2);
答案 0 :(得分:1)
var num = Math.val(prd.products_price);
var num = parseFloat(num);
var price=num.toFixed(2));
答案 1 :(得分:1)
var price = prd.products_price;
var product = price.formatMoney(0, "")
Number.prototype.formatMoney = function(places, symbol, thousand, decimal) {
places = !isNaN(places = Math.abs(places)) ? places : 2;
symbol = symbol !== undefined ? symbol : "$";
thousand = thousand || ",";
decimal = decimal || ".";
var number = this;
var negative = number < 0 ? "-" : "";
var i = parseInt(number = Math.abs(+number || 0).toFixed(places), 10) + "";
var j = (j = i.length) > 3 ? j % 3 : 0;
return symbol
+ negative
+ (j ? i.substr(0, j) + thousand : "")
+ i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + thousand)
+ (places ? decimal + Math.abs(number - i).toFixed(places).slice(2) : "");
}
答案 2 :(得分:0)
试试这个:
var price = parseFloat(prd.products_price).toFixed(2);