Question

我遇到了一个问题，这是我的代码，

          _bstr_t bstrTrans=L"2";
    wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans)//insert into database
//this can work fine, now we want to let bstrTrans add 1, likes this
            int bstrTrans2 = atoi(bstrTrans) + 1;
    wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans2 )
// now ,it cannot work.

所以任何人都可以帮助我吗？

Answer 1

未经测试，但它应该可以正常工作：

const _wchar_t pBuffer[16] = {0};
wsprintf(pBuffer, L"%u", bstrTrans2)
_bstr_t bstrTrans3(pBuffer);
wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans3 );

Answer 2

为什么不简单的s - ＆gt; d？

    _bstr_t bstrTrans=L"2";
    wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans) 

//insert into database
//this can work fine, now we want to let bstrTrans add 1, likes this
    int bstrTrans2 = atoi(bstrTrans) + 1;
    wsprintf(buf,L"insert into inven(ID) values(%d)",bstrTrans2 )

编辑：嗯，这个工作？

    _bstr_t bstrTrans=L"2";
    wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans) 

//insert into database
//this can work fine, now we want to let bstrTrans add 1, likes this
    char t[30];
    bstrTrans = itoa ( atoi (bstrTrans) + 1 , t,10);
    wsprintf(buf,L"insert into inven(ID) values(%s)",(wchar_t *)bstrTrans)

c ++将_bstr_t转换为int并将int转换为_bstr_t

2 个答案: