具有多个部分的UITableView

时间:2013-03-01 05:19:30

标签: iphone ipad uitableview

我想使用多个部分制作tableView但我不想使用字典我有两个数组我希望第一个数组应该在第一部分加载而第二部分在第二部分加载。

我有包含3个项目的arrayOne和包含4个项目的arrayTwo,因此如何添加它们并在各个部分中显示它们。

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section 
{
    if(section == 0)
        return resultArray.count;
    else
        return resultArray.count;
}

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView {
    return 2;
}


- (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section
{
    NSLog(@"Number of Sections");
    if(section == 0)
        return @"Section 1";
    if(section == 1)
        return @"Section 2";
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
     NSLog(@"Table Cell Data");
     static NSString *CellIdentifier = @"Cell";
     UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
     if (cell == nil) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier];
     }

     appDelegate = (MultipleDetailViewsWithNavigatorAppDelegate *)[[UIApplication sharedApplication] delegate];

     if (indexPath.section==0) {    
         appDelegate = (MultipleDetailViewsWithNavigatorAppDelegate *)[[UIApplication sharedApplication] delegate];
         ObjectData *theCellData = [resultArray objectAtIndex:indexPath.row];
         NSString *cellValue =theCellData.category;
         NSLog(@"Cell Values %@",cellValue);
         cell.textLabel.text = cellValue;
         return cell;
     }
     else {
         ObjectData *theCellData = [resultArray objectAtIndex:indexPath.row];
         NSString *cellValue =theCellData.category;
         cell.textLabel.text = cellValue;
         return cell;       
     }
}

6 个答案:

答案 0 :(得分:86)

 - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView {
      return 2 ;
 }

 - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section {
      if (section==0)
      {
             return [array1 count];
      }
      else{
             return [array2 count];
      }
 }

 - (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section {
      if(section == 0)
           return @"Section 1";
      else
           return @"Section 2";
 }


 - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath 
{

      static NSString *CellIdentifier = @"Cell";

      UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
     if (cell == nil) {
      cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier];
      }

 if (indexPath.section==0) {
     ObjectData *theCellData = [array1 objectAtIndex:indexPath.row];
     NSString *cellValue =theCellData.category;
     cell.textLabel.text = cellValue;
 }
 else {
     ObjectData *theCellData = [array2 objectAtIndex:indexPath.row];
     NSString *cellValue =theCellData.category;
     cell.textLabel.text = cellValue;
 }
     return cell;        
 }

答案 1 :(得分:1)

以下是相关的Swift 3系列:

func numberOfSections (in tableView: UITableView) -> Int {
    ...
    return numberOfSections
}

func tableView(_ tableView: UITableView, willDisplayHeaderView view: UIView, forSection section: Int) {
    //Not necessary, but will let you format the section headers. Example:
    guard let header = view as? UITableViewHeaderFooterView else { return }
    header.textLabel?.font = UIFont.boldSystemFont(ofSize: 24)
    header.textLabel?.textColor = UIColor.darkGray
    header.textLabel?.textAlignment = .center
    header.textLabel?.frame = header.frame
    view.tintColor = UIColor.white
}

func tableView(_ tableView: UITableView, willDisplayFooterView view: UIView, forSection section: Int) {
    //Also not necessary, but clear footers help space out sections
    view.tintColor = UIColor.clear   
}

func tableView(_ tableView: UITableView, heightForFooterInSection section: Int) -> CGFloat {
    //Spacing between sections:
    return 25
}

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    ...
    return sectionCount
}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    //All your cell setup
    ...
    //I call this to get the absolute row number (disregarding sections)
    let row = getAbsoluteRow_InCurrentSection(indexPath: indexPath)
    //Now you can use the row number to grab a value from an array or CoreData object and use the value to populate your cell!! 
}

func getAbsoluteRow_InCurrentSection(indexPath: IndexPath) -> Int {
    var aggRows = 0
    if currentListEntity == "GrocTask" {
        let curSection = indexPath.section
        for i in 0..<curSection {
            aggRows += flex1ArrayCnt[i]
        }
        aggRows += indexPath.row
    }
    return aggRows
}

//请注意,我只包含了与构建带有节的UITableView直接相关的内容。我没有包含editActions,didSelect或其他UITableView委托函数。

答案 2 :(得分:0)

更改此if (section==0)

if (indexPath.section==0)

你必须实现这个功能:

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section 
 {
     if(section == 0)
         return arrSection1.count;
      else
         return arrSection2.count;
 }

答案 3 :(得分:0)

您的numberOfRowsInSection应该是这样的:

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section {
    if (section == 0) {
        return firstArray.count;
    } else {
        return secondArray.count;
    }
}

答案 4 :(得分:0)

你几乎正确......

让我们考虑您的两个数组是arrOnearrTwo .....

    - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section {
      if(section == 0)
      return [arrOne count];
      else
      return [arrTwo count];
    }

    - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath 
        {

         static NSString *CellIdentifier = @"Cell";

         UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
        if (cell == nil) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier];
          }

             if (indexPath.section==0) {


        ObjectData *theCellData = [arrOne objectAtIndex:indexPath.row];
        NSString *cellValue =theCellData.category;
        NSLog(@"cellValue = %@",cellValue); //To see the value of string cellValue
        cell.textLabel.text = cellValue;

        return cell;

    }

    else {
        ObjectData *theCellData = [arrTwo objectAtIndex:indexPath.row];
        NSString *cellValue =theCellData.category;
        cell.textLabel.text = cellValue;

        return cell;        
    }
}

答案 5 :(得分:0)

TableView委托方法已将该部分作为 :( NSInteger)部分 ..所以我们也可以使用switchCase

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
    {
        switch (section)
        {
            case 0:
                return self.arrMedia.count;
                break;
            case 1:
                return 1;
                break;
        }
        return 0;
    }