Question source: SPOJ.. ORDERS
def swap(ary,idx1,idx2):
tmp = ary[idx1]
ary[idx1] = ary[idx2]
ary[idx2] = tmp
def mkranks(size):
tmp = []
for i in range(1, size + 1):
tmp = tmp + [i]
return tmp
def permutations(ordered, movements):
size = len(ordered)
for i in range(1, size): # The leftmost one never moves
for j in range(0, int(movements[i])):
swap(ordered, i-j, i-j-1)
return ordered
numberofcases = input()
for i in range(0, numberofcases):
sizeofcase = input()
tmp = raw_input()
movements = ""
for i in range(0, len(tmp)):
if i % 2 != 1:
movements = movements + tmp[i]
ordered = mkranks(sizeofcase)
ordered = permutations(ordered, movements)
output = ""
for i in range(0, sizeofcase - 1):
output = output + str(ordered[i]) + " "
output = output + str(ordered[sizeofcase - 1])
print output
答案 0 :(得分:1)
让您的代码更加Pythonic(但不改变其流程/算法):
def swap(ary, idx1, idx2):
ary[idx1], ary[idx2] = [ary[i] for i in (idx2, idx1)]
def permutations(ordered, movements):
size = len(ordered)
for i in range(1, len(ordered)):
for j in range(movements[i]):
swap(ordered, i-j, i-j-1)
return ordered
numberofcases = input()
for i in range(numberofcases):
sizeofcase = input()
movements = [int(s) for s in raw_input().split()]
ordered = [str(i) for i in range(1, sizeofcase+1)]
ordered = permutations(ordered, movements)
output = " ".join(ordered)
print output
我看到它在您指明的SPOJ URL中给出的示例案例中正确运行。你的失败案例是什么?