Question

我在解析时检索对象，但它总是转到ParseException

这是我的代码：

public void setItemListData(Context context, String className, 
            String[] value, String colName) {
        ParseQuery query = new ParseQuery(className);
        query.whereContainsAll("Store",Arrays.asList (value));
        query.whereEqualTo("Store","Asus");
        dataList = new ArrayList<String>();
        try {
            List<ParseObject> dataHolder = query.find();
            for(int counter =0;counter<dataHolder.size();counter++){
                String datas = dataHolder.get(counter).getString(colName);
                dataList.add(datas);    
            }
        } catch (ParseException e) {
            Toast.makeText(context,"No Internet Connection",
            Toast.LENGTH_SHORT).show();
        }
    }

我不知道我的代码有什么问题

提前致谢

Answer 1

Change query.whereContainsAll("Store",Arrays.asList (value));

到

query.whereContainedIn("Store",Arrays.asList (value));

Answer 2

在单个查询中找到多个值：

private List<ParseObject> todos;

查找多个值的代码：

ParseQuery<ParseObject> query = new ParseQuery<ParseObject>("Your_Class_Name");
String[] names = {"Hiren", "Dhruv", "Pratik", "Miral", "Kirit"};
   query.whereContainedIn("Your_Column_Name_Means_Key", Arrays.asList(names));
    try {
         todos = query.find();
         Log.i("No Of Record Found",todos.size()+"");
        }catch (ParseException e) {
         e.printStackTrace()
        }

您必须传递您的类名和您的列名。

完成

解析检索与几个不同值匹配的数据

2 个答案: