Question

档案格式

POS ID         PosScore NegScore    SynsetTerms                          Gloss
a   00001740    0.125   0           able#1"                              able to swim"; "she was able to program her computer";
a   00002098    0       0.75        unable#1                            "unable to get to town without a car"; 
a   00002312    0       0           dorsal#2 abaxial#1                  "the abaxial surface of a leaf is the underside or side facing away from the stem"
a   00002843    0       0           basiscopic#1                         facing or on the side toward the base
a   00002956    0       0.23        abducting#1 abducent#1               especially of muscles; drawing away from the midline of the body or from an adjacent part
a   00003131    0       0           adductive#1 adducting#1 adducent#1   especially of muscles;

在此文件中，我想提取（ID，PosScore，NegScore和SynsetTerms）字段。 （ID，PosScore，NegScore）字段数据提取很简单，我使用以下代码来获取这些字段的数据。

Regex expression = new Regex(@"(\t(\d+)|(\w+)\t)");

var results = expression.Matches(input);
foreach (Match match in results)
{

    Console.WriteLine(match);
}
Console.ReadLine();

并且它给出了正确的结果但是归档 SynsetTerms 会产生问题，因为有些行有两个或更多单词，所以如何组织单词并反对它PosScore和NegScore。

例如，在第五行中有两个单词abducting#1和abducent#1，但两者都有相同的分数。

那么获得Word及其得分的行是什么样的正则表达式，如：

  Word                PosScore          NegScore 
  abducting#1         0                 0.23
  abducent#1          0                 0.23

Answer 1

非正则表达式，字符串拆分版本可能更容易：

var data =
   lines.Split(new[] {Environment.NewLine}, StringSplitOptions.RemoveEmptyEntries)
        .Skip(1)
        .Select(line => line.Split('\t'))
        .SelectMany(parts => parts[4].Split().Select(word => new
            {
                ID = parts[1],
                Word = word,
                PosScore = decimal.Parse(parts[2]),
                NegScore = decimal.Parse(parts[3])
            }));

Answer 2

您可以使用此正则表达式

^(?<pos>\w+)\s+(?<id>\d+)\s+(?<pscore>\d+(?:\.\d+)?)\s+(?<nscore>\d+(?:\.\d+)?)\s+(?<terms>(?:.*?#[^\s]*)+)\s+(?<gloss>.*)$

您可以创建一个像这样的列表

var lst=Regex.Matches(input,regex)
             .Cast<Match>()
             .Select(x=>
             new 
             {
                 pos=x.Groups["pos"].Value,
                 terms=Regex.Split(x.Groups["terms"].Value,@"\s+"),
                 gloss=x.Groups["gloss"].Value
             }
        );

现在你可以迭代它了

foreach(var temp in lst)
{
    temp.pos;
    //you can now iterate over terms
    foreach(var t in temp.terms)
    {
    }
}

在c＃中匹配不同格式句子的正则表达式

2 个答案: