Question

给定路径和某个部分，如何找到该部分正下方的文件夹名称？

这很难解释，让我举一些例子。假设我在'Dev / Branches'下面找到文件夹的名称。以下是示例输入，预期结果以粗体显示

C：\ Code \ Dev \ Branches \ 最新 \ bin \ abc.dll
C：\ Dev \ Branches \ 5.1
D：\我的文档\分支\ 7.0 \ Source \ Tests \ test.cs

我正在使用C＃

编辑：我想我可以使用正则表达式/Dev/Branches/(.*?)/捕获第一组，但有没有正则表达式的整洁解决方案？无论如何，正则表达式会在第二种情况下失败。

Answer 1

// starting path
string path = @"C:\Code\Dev\Branches\Latest\bin\abc.dll";

// search path
string search = @"Dev\Branches";

// find the index of the search criteria
int idx = path.IndexOf(search);

// determine whether to exit or not
if (idx == -1 || idx + search.Length >= path.Length) return;

// get the substring AFTER the search criteria, split it and take the first item
string found = path.Substring(idx + search.Length).Split("\\".ToCharArray(), StringSplitOptions.RemoveEmptyEntries).First();

Console.WriteLine(found);

Answer 2

以下代码将完全符合您的预期：

public static string GetSubdirectoryFromPath(string path, string parentDirectory, bool ignoreCase = true)
{
    // 1. Standarize the path separators.
    string safePath = path.Replace("/", @"\");
    string safeParentDirectory = parentDirectory.Replace("/", @"\").TrimEnd('\\');

    // 2. Prepare parentDirectory to use in Regex.
    string directory = Regex.Escape(safeParentDirectory);

    // 3. Find the immediate subdirectory to parentDirectory.
    Regex match = new Regex(@"(?:|.+)" + directory + @"\\([^\\]+)(?:|.+)", ignoreCase ? RegexOptions.IgnoreCase : RegexOptions.None);

    // 4. Return the match. If not found, it returns null.
    string subDirectory = match.Match(safePath).Groups[1].ToString();
    return subDirectory == "" ? null : subDirectory;
}

测试代码：

void Test()
{
    string path1 = @"C:\Code\Dev\Branches\Latest\bin\abc.dll";
    string path2 = @"C:\Dev\Branches\5.1";
    string path3 = @"D:\My Documents\Branches\7.0\Source\test.cs";

    Console.WriteLine("Matches:");
    Console.WriteLine(GetSubdirectoryFromPath(path1, "dev/branches/") ?? "Not found");
    Console.WriteLine(GetSubdirectoryFromPath(path1, @"Dev\Branches") ?? "Not found");
    Console.WriteLine(GetSubdirectoryFromPath(path3, "D:/My Documents/Branches") ?? "Not found");
    // Incorrect parent directory.
    Console.WriteLine(GetSubdirectoryFromPath(path2, "My Documents") ?? "Not found");
    // Case sensitive checks.
    Console.WriteLine(GetSubdirectoryFromPath(path3, @"My Documents\Branches", false) ?? "Not found");
    Console.WriteLine(GetSubdirectoryFromPath(path3, @"my Documents\Branches", false) ?? "Not found");

    // Output:
    //
    // Matches:
    // Latest
    // Latest
    // 7.0
    // Not found
    // 7.0
    // Not found
}

Answer 3

将其分解为更小的步骤，您可以自己解决：

（可选，取决于其他要求）：获取目录名称（文件无关紧要）：Path.GetDirectoryName(string)
获取其父目录Directory.GetParent(string)。

这归结为;

 var directory = Path.GetDirectoryName(input);
 var parentDirectory = Directory.GetParent(directory);

提供的C:\Dev\Branches\5.1 - ＆gt; 5.1不符合您的规范，即输入路径本身的目录名称。这将输出Branches。

Answer 4

new Regex("\\?" + PathToMatchEscaped + "\\(\w+)\\?").Match()...

Answer 5

我选择了这个

public static string GetBranchName(string path, string prefix)
{
    string folder = Path.GetDirectoryName(path);

    // Walk up the path until it ends with Dev\Branches
    while (!String.IsNullOrEmpty(folder) && folder.Contains(prefix))
    {
        string parent = Path.GetDirectoryName(folder);
        if (parent != null && parent.EndsWith(prefix))
            return Path.GetFileName(folder);

        folder = parent;
    }

    return null;
}

如何在路径的给定部分下找到文件夹？

5 个答案: