给出一个包含2列的表
Name(type VARCHAR) Time(type DATETIME)
我需要编写一个SQL查询来查找条目数最多的小时。
例如:
Name Time
---- ----
a 12:30pm
b 12:05pm
c 13:55pm
d 12:50pm
e 01:02am
期望的结果是小时:中午12点 - 下午1点
我的一般想法是:
1)按小时分组行
2)计算行/组
3)按降序排列计数
4)打印最大计数
我需要帮助将其转换为SQL查询。
答案 0 :(得分:3)
这非常简单......
SELECT HOUR(Time) as Hr,COUNT(*) AS Cnt
FROM MyTable
GROUP BY Hour(Time)
ORDER BY Cnt DESC
LIMIT 1
GROUP BY Hour(Time)
- 按小时分组
ORDER BY Cnt DESC
- 这使得它按计数排序(按降序排列)
LIMIT 1
- 因为您只需要一个最佳结果
答案 1 :(得分:0)
这是我理解你正在寻找的Oracle版本:
SELECT t_stamp
, MAX(count(t_stamp)) OVER (PARTITION BY t_stamp ORDER BY t_stamp) hits_per_hr_interval
FROM
(
SELECT name, EXTRACT(hour From Cast(t_stamp as timestamp)) t_stamp
FROM stack_test
)
GROUP BY t_stamp
/
T_STAMP HITS_PER_HR_INTERVAL
-------------------------------
12 3
13 2
或使用row_number():
SELECT * FROM
(
SELECT t_stamp
, Count(t_stamp) OVER (PARTITION BY t_stamp ORDER BY t_stamp) hits_per_hr_interval
, ROW_NUMBER() OVER (PARTITION BY t_stamp ORDER BY t_stamp) hr_seq
FROM
(
SELECT EXTRACT(hour From Cast(t_stamp as timestamp)) t_stamp
FROM stack_test
)
)
-- WHERE hr_seq = 1 -- optional to see only first row per group as in above example
/
T_STAMP HITS_PER_HR_INTERVAL HR_SEQ
------------------------------------------
12 3 1
12 3 2
12 3 3
13 2 1
13 2 2
您可以添加更多过滤器,例如您的小时数在12到1之间......