Question

我有一个像{ASK(Value, Value, 'Sentence', Some_Char)}这样的字符串，我需要在()中获得爆炸值。我做错了什么？

preg_match_all('/\{ASK\((.*?),\)\}/', '{ASK(Value, Value, \'Sentence\', X)}', $matches);
print_r($matches);

Answer 1

从正则表达式中取出逗号，然后匹配。

preg_match_all('/\{ASK\((.*?)\)\}/', '{ASK(Value, Value, \'Sentence\', X)}', $matches);
print_r($matches);

//Explode the matched group
$exploded = explode(',',$matches[1]); 
print_r($exploded);

/*
 * Note that we used $matches[1] instead of $matches[0], 
 * since the first element contains the entire matched 
 * expression, and each subsequent element contains the matching groups.
 */

Answer 2

$s = "{ASK(Value, Value, 'Sentence', Some_Char)}";
$p = '#\{ASK\((.*?)\)\}#';
preg_match_all($p, $s, $matches);
print_r($matches);

Answer 3

简单拆分＆amp;爆炸

$Myval = "{ASK(Value, Value, 'Sentence', Some_Char)}";

$splitedVal = split('[()]', $Myval);

$explodedVal = explode(",", $splitedVal[1]);

print_r($explodedVal);

//输出

Array ( [0] => Value [1] => Value [2] => 'Sentence' [3] => Some_Char )

Answer 4

执行此操作的简单方法（尽管未完全包含在正则表达式中）可能是：

preg_match_all('/\{ASK\([^)]*\)\}/', '{ASK(Value, Value, \'Sentence\', X)}', $matches);
$values = explode($matches[1]);

Answer 5

只要您的Values，Sentences和Chars不包含,或)，那么此单一正则表达式模式将无需额外提供explode()致电。

模式：~(?:\G, |ASK\()\K[^,)]+~（Pattern Demo）

代码：（Demo）

$string="{ASK(Value, Value, 'Sentence', Some_Char)}";

print_r(preg_match_all('~(?:\G, |ASK\()\K[^,)]+~',$string,$out)?$out[0]:[]);

输出：

Array
(
    [0] => Value
    [1] => Value
    [2] => 'Sentence'
    [3] => Some_Char
)

＆＃34;魔法＆＃34;在\G。这告诉正则表达式在字符串的开头或之前的匹配之后继续匹配。以下是我发布的类似答案：https://stackoverflow.com/a/48373347/2943403

爆炸与正则表达式

5 个答案: