所以我的Boolean方法运行并返回正确的true或false ....但我需要某种扫描程序函数来获取返回if语句后面的内容。这是我的主要代码。任何帮助表示赞赏!此外,我的柜台不起作用:(我是新人。
import java.util.Random;
import java.util.Scanner;
public class CrapsP5 {
public static void main(String[] args) {
int number = 0, total, counter;
total = counter = 0;
String response;
Scanner console = new Scanner(System. in );
//1
System.out.println("Would you like to play craps? (Y/N)");
response = console.next();
if (response.equalsIgnoreCase("N")) {
System.exit(0);
}
//2
System.out.println("Welcome to craps. Would you like to see the rules? (Y/N)");
response = console.next();
if (response.equalsIgnoreCase("Y")) {
rules();
}
//3 call play method
play();
//I need something here to act like the scanner console does?? yes?? but what?
if (true) {
System.out.println("Congrats! You've won!");
counter++; //add 1 to win count (w)
total = counter;
play();
}
if (false) {
System.out.println("I'm sorry, you've lost.");
System.exit(0);
}
//4
System.out.println("Thanks for playing! You won " + total + " number of times before losing.");
答案 0 :(得分:0)
这是你的布尔方法?玩()? 如果是的话
boolean result = play();
if(result){
...
}
else{
...
}
或
if(play()){
...
} else {
...
}
答案 1 :(得分:0)
尝试:
if(play())
{
....
}
else
{
}
如果你的play()返回布尔值。
答案 2 :(得分:0)
我想指出这一点:
play();
if (true) {
System.out.println("Congrats! You've won!");
counter++; //add 1 to win count (w)
total = counter;
play();
}
说,用户第一次玩,如果他赢了,流进入条件区,并且进行另一次游戏调用。无论用户第二次赢或输第二次,计数器都会不要改变,游戏结束,执行:
System.out.println("Thanks for playing! You won " + total + " number of times before losing.");
我建议使用while循环继续播放,直到用户输掉。如:
while(play()){
System.out.println("Congrats! You've won!");
counter++;
total = counter;
}
//It is assumed that the counter and eventually the game should restart on losing
System.out.println("I'm sorry, you've lost.");
System.out.println("Thanks for playing! You won " + total + " number of times before losing.");