php / mysql +填充3下拉菜单

时间：2013-02-28 06:10:11

标签： php mysql drop-down-menu dreamweaver

嘿伙计我正在开发一个页面，其中我填充了多个下拉菜单，其中包含从数据库中检索到的数据，但问题是我只能填充一个下拉菜单如果有人可以帮助我PLZ，如何能够填充多个

func.inc.php

<?php
 require_once('db.inc.php'); 

function connect(){
   mysql_connect(DB_Host, DB_User ,DB_Pass )or die("could not connect to the database" .mysql_error());

   mysql_select_db(DB_Name)or die("could not select database");

}
  function close(){

  mysql_close();

  }

  function countryQuery(){

  $countryData = mysql_query("SELECT * FROM country");

  while($record = mysql_fetch_array($countryData)){

     echo'<option value="' . $record['country_name'] .  '">' . $record['country_name'] . '</option>';

  }

}

function specializationQuery(){

$specData = mysql_query("SELECT * FROM specialization");

  while($recordJob = mysql_fetch_array($specData)){

     echo'<option value="' . $recordJob['specialization_name'] .  '">' . $recordJob['specialization_name'] . '</option>';

  }


}
?>

的index.php

<?php
  require_once('func.inc.php'); 
  connect(); 


?>


<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>testDroplistdown</title>
</head>

<body>
<p align="center">
<select name="dropdown">
  <?php countryQuery(); ?>
</select>
  <?php close(); ?>
</p>
<p align="left">
<select name="dropdown2">
  <?php specializationQuery(); ?>
</select>
  <?php close(); ?>
</p>


</body>
</html>

1 个答案:

答案 0 :(得分：0)

您似乎正在关闭连接而不是重新连接。删除第一个关闭（）并尝试一下