我正在开发小型Android应用程序,其中我将drawable资源设置为线性布局的背景。现在,我想要做的是动态地改变线性布局的背景颜色,但是在可绘制资源中。 我的代码如下:
// bcd.xml
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item>
<shape>
<gradient
android:endColor="#22000000"
android:startColor="#22000000"
android:angle="270" />
<stroke
android:width="3dp"
android:color="@color/white" />
<corners
android:radius="3dp" />
<padding
android:left="10dp"
android:top="10dp"
android:right="10dp"
android:bottom="10dp" />
</shape>
</item>
<LinearLayout
android:id="@+id/lin_llt"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
>
我在我的活动中为线性布局设置了背景......
parentLayout = (LinearLayout) view.findViewById(R.id.lin_llt);
parentLayout.setBackgroundResource(R.drawable.bcd);
现在我想做什么我想改变我的可绘制资源的颜色,这意味着改变我的线性布局的颜色,圆角和填充在drawable中定义..
我按照以下方式尝试了这个
ShapeDrawable bgShape = (ShapeDrawable )parentLayout.getBackground();
bgShape.getPaint().setColor(Color.BLACK);
但它不适合我。任何其他解决方案。
那怎么办...... 需要帮忙... 谢谢......
答案 0 :(得分:26)
动态更改布局颜色
LinearLayout Layout = (LinearLayout) findViewById(R.layout.id);
Layout.setBackgroundColor(Color.parseColor("#ffffff"));
动态设置背景颜色渐变
View layout = findViewById(R.id.mainlayout);
GradientDrawable gd = new GradientDrawable(
GradientDrawable.Orientation.TOP_BOTTOM,
new int[] {0xFF616261,0xFF131313});
gd.setCornerRadius(0f);
layout.setBackgroundDrawable(gd);
答案 1 :(得分:11)
您可以尝试这样的事情:
Drawable sampleDrawable = context.getResources().getDrawable(R.drawable.balloons);
sampleDrawable.setColorFilter(new PorterDuffColorFilter(0xffff00,PorterDuff.Mode.MULTIPLY));
您可以参考:
How to change colors of a Drawable in Android?
Change drawable color programmatically
Android: Change Shape Color in runtime
你也可以试试这个:
private static final int[] FROM_COLOR = new int[]{49, 179, 110};
private static final int THRESHOLD = 3;
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.test_colors);
ImageView iv = (ImageView) findViewById(R.id.img);
Drawable d = getResources().getDrawable(RES);
iv.setImageDrawable(adjust(d));
}
private Drawable adjust(Drawable d)
{
int to = Color.RED;
//Need to copy to ensure that the bitmap is mutable.
Bitmap src = ((BitmapDrawable) d).getBitmap();
Bitmap bitmap = src.copy(Bitmap.Config.ARGB_8888, true);
for(int x = 0;x < bitmap.getWidth();x++)
for(int y = 0;y < bitmap.getHeight();y++)
if(match(bitmap.getPixel(x, y)))
bitmap.setPixel(x, y, to);
return new BitmapDrawable(bitmap);
}
private boolean match(int pixel)
{
//There may be a better way to match, but I wanted to do a comparison ignoring
//transparency, so I couldn't just do a direct integer compare.
return Math.abs(Color.red(pixel) - FROM_COLOR[0]) < THRESHOLD && Math.abs(Color.green(pixel) - FROM_COLOR[1]) < THRESHOLD && Math.abs(Color.blue(pixel) - FROM_COLOR[2]) < THRESHOLD;
}
中给出
答案 2 :(得分:2)
使用此.. ..
<solid android:color="#e1e1e1" />
<stroke
android:width="2dp"
android:color="#808080" />
<corners android:radius="10dp" />
<padding
android:bottom="5dp"
android:left="5dp"
android:right="5dp"
android:top="5dp" />
答案 3 :(得分:1)
一种方法是使用第二种颜色创建第二个可绘制的XML,然后使用第二个drawable更改布局的背景。
答案 4 :(得分:1)
以下作品非常适合以编程方式设置可绘制的颜色,不用更改其形状:
parentLayout.getBackground().setColorFilter(
Color.BLACK,
PorterDuff.Mode.SRC_ATOP
);
答案 5 :(得分:0)
也可以使用:
val layerDrawable : LayerDrawable = imageView.background as LayerDrawable
val bgShape = layerDrawable.findDrawableByLayerId(R.id.shape_id) as GradientDrawable
bgShape.setColor(ContextCompat.getColor(context, R.color.colorPrimary))
带示例( drawable / circle.xml ):
<?xml version="1.0" encoding="utf-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item android:id="@+id/shape_id">
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="rectangle">
<corners android:radius="1000dp" />
<solid android:color="#F4B528" />
<padding
android:bottom="4dp"
android:left="4dp"
android:right="4dp"
android:top="4dp" />
</shape>
</item>
</layer-list>
和 ImageView :
<ImageView
android:id="@+id/imageView"
android:layout_width="16dp"
android:layout_height="16dp"
android:background="@drawable/circle"
/>