Question

我希望有人可以帮助我，因为我没有得到回应，没有错误，也没有迹象表明为什么我的CURL不能在这里工作。我已经搜索并添加了一个忽略SSL的条款（SSLVerify设置为false）并尝试了多种方式来获得响应。

请有人请我指出正确的方向吗？

谢谢！

<?php
function sendContactInfo() {

//Process a new form submission in HubSpot in order to create a new Contact.

$hubspotutk = $_COOKIE['hubspotutk'];  //grab the cookie from the visitors browser.
$ip_addr = $_SERVER['REMOTE_ADDR'];  //IP address too.
$hs_context = array(
        'hutk' => $hubspotutk,
        'ipAddress' => $ip_addr,
        'pageUrl' => 'https://www.myfoodstorage.com/onestepcheckout/',
        'pageTitle' => 'MyFoodStorage.com Cart Checkout'
    );
$hs_context_json = json_encode($hs_context);

//Need to populate these varilables with values from the form.
$str_post = "firstname=" . urlencode($firstname)
        . "&lastname=" . urlencode($lastname)
        . "&email=" . urlencode($email)
        . "&phone=" . urlencode($telephone)
        . "&address=" . urlencode($street)
        . "&city=" . urlencode($city)
        . "&state=" . urlencode($region)
        . "&country=" . urlencode($country)
        . "&hs_context=" . urlencode($hs_context_json);  //Leave this one be :)

 //replace the values in this URL with your portal ID and your form GUID
$endpoint = 'https://forms.hubspot.com/uploads/form/v2/234423/4a282b6b-2ae2-4908-bc82-b89874f4e8ed';

$ch = @curl_init();
@curl_setopt($ch, CURLOPT_POST, true);
@curl_setopt($ch, CURLOPT_POSTFIELDS, $str_post);
@curl_setopt($ch, CURLOPT_URL, $endpoint);
@curl_setopt($ch, CURLOPT_HTTPHEADER, array('application/x-www-form-urlencoded'));
@curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
@curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
$response = @curl_exec($ch);
$info = @curl_getinfo($ch);
@curl_close($ch);
}

echo sendContactInfo();
echo $response;
print_r($info);
?>

Answer 1

1.您无法打印在函数外部的函数内定义的变量值，如下所示：

function sendContactInfo() {

 $response = @curl_exec($ch);

 $info = @curl_getinfo($ch);

}

echo $response;

print_r($info);

但你可以打印价值：

function sendContactInfo() {

 $response = @curl_exec($ch);

 $info = @curl_getinfo($ch);

 echo $response;

 print_r($info);

}

sendContactInfo();

2.当你想运行函数并获得值后，使用“return”，如下所示：

function sendContactInfo() {

 $response = @curl_exec($ch);

 $info = @curl_getinfo($ch);

 return $response;

 //or return $info;, when you want to get array values from @curl_getinfo

}

print_r(sendContactInfo());

Answer 2

sendContactInfo是一个函数，但它没有被用作一个函数。

您无法访问函数内部使用的变量。它还需要返回一些东西

变化：

$response = @curl_exec($ch);

到

return @curl_exec($ch);

CURL - 没有回应，也没有错误

2 个答案: