我试图将node-http-proxy用作反向代理,但我似乎无法使POST和PUT请求起作用。文件server1.js是反向代理(至少对于具有url" / forward-this"的请求),server2.js是接收代理请求的服务器。请解释我做错了什么。
这是server1.js的代码:
// File: server1.js
//
var http = require('http');
var httpProxy = require('http-proxy');
httpProxy.createServer(function (req, res, proxy) {
if (req.method == 'POST' || req.method == 'PUT') {
req.body = '';
req.addListener('data', function(chunk) {
req.body += chunk;
});
req.addListener('end', function() {
processRequest(req, res, proxy);
});
} else {
processRequest(req, res, proxy);
}
}).listen(8080);
function processRequest(req, res, proxy) {
if (req.url == '/forward-this') {
console.log(req.method + ": " + req.url + "=> I'm going to forward this.");
proxy.proxyRequest(req, res, {
host: 'localhost',
port: 8855
});
} else {
console.log(req.method + ": " + req.url + "=> I'm handling this.");
res.writeHead(200, { "Content-Type": "text/plain" });
res.write("Server #1 responding to " + req.method + ": " + req.url + "\n");
res.end();
}
}
这里是server2.js的代码:
// File: server2.js
//
var http = require('http');
http.createServer(function (req, res, proxy) {
if (req.method == 'POST' || req.method == 'PUT') {
req.body = '';
req.addListener('data', function(chunk) {
req.body += chunk;
});
req.addListener('end', function() {
processRequest(req, res);
});
} else {
processRequest(req, res);
}
}).listen(8855);
function processRequest(req, res) {
console.log(req.method + ": " + req.url + "=> I'm handling this.");
res.writeHead(200, { 'Content-Type': 'text/plain' });
res.write("Server #2 responding to " + req.method + ': url=' + req.url + '\n');
res.end();
}
答案 0 :(得分:5)
http-proxy取决于POST / PUT请求的data
和end
事件。 server1接收请求的时间与代理请求之间的延迟意味着http-proxy完全错过了这些事件。您有两个选项可以让它正常工作 - 您可以buffer the request或者您可以使用routing proxy。路由代理似乎最合适,因为您只需要代理一部分请求。这是修改后的server1.js:
// File: server1.js
//
var http = require('http');
var httpProxy = require('http-proxy');
var proxy = new httpProxy.RoutingProxy();
http.createServer(function (req, res) {
if (req.url == '/forward-this') {
return proxy.proxyRequest(req, res, {
host: 'localhost',
port: 8855
});
}
if (req.method == 'POST' || req.method == 'PUT') {
req.body = '';
req.addListener('data', function(chunk) {
req.body += chunk;
});
req.addListener('end', function() {
processRequest(req, res);
});
} else {
processRequest(req, res);
}
}).listen(8080);
function processRequest(req, res) {
console.log(req.method + ": " + req.url + "=> I'm handling this.");
res.writeHead(200, { "Content-Type": "text/plain" });
res.write("Server #1 responding to " + req.method + ": " + req.url + "\n");
res.end();
}
答案 1 :(得分:2)
除了@squamos
How to write a node express app that serves most local files, but reroutes some to another domain?
var proxy = new httpProxy.RoutingProxy();
"上面的代码适用于http-proxy~0.10.x。从那以后,很多东西在图书馆里发生了变化。您可以在下面找到新版本的示例(在编写时为~1.0.2)"
var proxy = httpProxy.createProxyServer({});
答案 2 :(得分:1)
这是我的代理POST请求的解决方案。这不是最理想的解决方案,但它有效且易于理解。
var request = require('request');
var http = require('http'),
httpProxy = require('http-proxy'),
proxy = httpProxy.createProxyServer({});
http.createServer(function(req, res) {
if (req.method == 'POST') {
request.post('http://localhost:10500/MyPostRoute',
{form: {}},
function(err, response, body) {
if (! err && res.statusCode == 200) {
// Notice I use "res" not "response" for returning response
res.writeHead(200, {'Content-Type': "application/json"});
res.end(body);
}
else {
res.writeHead(404, {'Content-Type': "application/json"});
res.end(JSON.stringify({'Error': err}));
}
});
}
else if (req.method == 'GET') {
proxy.web(req, res, { target: 'http://localhost/9000' }, function(err) {
console.log(err)
});
}
端口10500
和9000
是任意的,在我的代码中,我根据我托管的服务动态分配它们。这不涉及PUT,它可能效率较低,因为我正在创建另一个响应,而不是操纵当前的响应。