的index.php

Question

任何人都可以告诉我这个大坝代码中的错误是什么我疯狂地搜索错误但没有任何成功错误是我没有从表中获取任何数据为什么会发生？请帮助我

的index.php

<html>
<head>
</head>
<body>
<form action="index.php" method="post">
<label for="searchByCountry">By Country</label>
            <select name="searchByCountry" id="searchByCountry">
             <option id="0">--select your country--</option>
             <?php
                 require_once('connfor_lamelchameltest.php'); 



               $getallCountries = mysql_query("SELECT country_name FROM country") or die("could not search for countries");
         if(mysql_num_rows($getallCountries) > 0) {

               while($viewallCountries = mysql_fetch_array($getallCountries)){

                ?>

               <option id="<?php echo $viewallCountries['country_name']; ?> "></option>
                 <?php } ?>
               <?php } ?>

            </select>
 </form>
 </body>
 </html>

Answer 1

<html>
<head>
</head>
<body>
<form action="index.php" method="post">
<label for="searchByCountry">By Country</label>
            <select name="searchByCountry" id="searchByCountry">
             <option id="0">--select your country--</option>
             <?php
                 require_once('connfor_lamelchameltest.php'); 



               $getallCountries = mysql_query("SELECT country_name FROM country") or die("could not search for countries");
         if(mysql_num_rows($getallCountries) > 0) {

               while($viewallCountries = mysql_fetch_array($getallCountries)){

                ?>

               <option value="<?php echo $viewallCountries['country_name']; ?> ">
<?php echo $viewallCountries['country_name']; ?>
</option>
                 <?php } ?>
               <?php } ?>

            </select>
 </form>
 </body>
 </html>

检索数据并在下拉列表中显示（php / mysql）

的index.php

1 个答案: