Question

尝试查找这两个查询是否有重叠

以下PHP / MYSQL代码有效，但它很笨重;两个查询，数据转换成数组，比较数组！

（注意这是一个函数，因为它返回是否有重叠）

$manager_sql = "SELECT league_id FROM league_members WHERE manager = 1 AND member_active = 1 AND player_id = $mi";
$player_sql = "SELECT league_id FROM league_members WHERE member_active = 1 AND player_id = $pi";

$manager_result = mysql_query($manager_sql) or die(mysql_error());
$manager_leagues = array();
while($sqlrow = mysql_fetch_array($manager_result)) {
    extract( $sqlrow );
    $manager_leagues[] = $league_id;
}

$player_result = mysql_query($player_sql) or die(mysql_error());
$player_leagues = array();
while($sqlrow = mysql_fetch_array($player_result)) {
    extract( $sqlrow );
    $player_leagues[] = $league_id;
}

$result = array_intersect($manager_leagues, $player_leagues);

return count($result) > 0;

以下是一次尝试进行查询的尝试：

(SELECT league_id FROM league_members WHERE manager = 1 AND member_active = 2 AND player_id = '$mi')
    UNION ALL
(SELECT league_id FROM league_members WHERE member_active = 1 AND player_id = '$pi')

似乎工作，但返回太多行：

SELECT league_id FROM league_members WHERE league_id IN (
    SELECT league_id FROM league_members WHERE manager = 1 AND member_active = 1 AND player_id = '$mi'
) AND league_id IN (
    SELECT league_id FROM league_members WHERE member_active = 1 AND player_id = '$pi'
)

Answer 1

尝试此查询：

$sql = "SELECT ls1.league_id FROM league_members AS ls1
        INNER JOIN league_members AS ls2 ON ls1.league_id = ls2.league_id
        WHERE ls1.manager = 1 AND ls1.member_active = 1 AND ls1.player_id = '".$mi."' 
        AND ls2.member_active = 1 AND ls2.player_id = '".$pi."'"

注意：

mysql_ *函数被删除，使用mysqli_ *函数或PDO
您的查询容易受到sql注入，请将其设为seccure。

Answer 2

您希望找到任何同时拥有$mi作为经理且$pi作为其中一名玩家的联盟？

SELECT DISTINCT l.league_id FROM league_members l JOIN league_members l2 ON l.league_id = l2.league_id AND l.member_active = 1 AND l2.member_active = 1 AND l.manager = 1 AND l2.manager = 0 WHERE l.player_id = $mi AND l2.player_id = $pi;

Answer 3

试

"SELECT league_id FROM league_members WHERE manager = 1 AND member_active = 1 AND (player_id = '".$mi."' OR player_id = '".$pi."')";

Answer 4

请尝试以下它会工作。如果没有，那么请让我知道你遇到了什么样的问题。

SELECT league_id FROM league_members WHERE league_id IN（ SELECT league_id FROM league_members WHERE（member_active = 1 AND（player_id ='$ mi'或player_id ='$ pi'）AND manager = 1）

Answer 5

我显然没有尝试过这个，但我建议使用distinct关键字添加最后一个查询：

SELECT distinct league_id FROM league_members WHERE league_id IN (
    SELECT league_id FROM league_members WHERE manager = 1 AND member_active = 1 AND player_id = '$mi'
) AND league_id IN (
    SELECT league_id FROM league_members WHERE member_active = 1 AND player_id = '$pi'
)

Answer 6

怎么样？

SELECT league_id 
FROM   league_members 
WHERE  (manager = 1 AND member_active = 1 AND player_id = $mi) OR
       (member_active = 1 AND player_id = $pi)
GROUP  BY league_id
HAVING COUNT(*) = 2

从一个表中获取两个查询的重叠

6 个答案: