我在这段代码中遇到了麻烦(我在本地PC上工作)。
求助于你。
我的代码如下:
<html>
<head>
<title>My Test</title>
<script src="../jquery/js/jquery-1.9.0.min.js"></script>
</head>
<body>
<script>
var _canvas = document.createElement('canvas');
_canvas.width="100";
_canvas.height="100";
var _context = _canvas.getContext("2d");
var _img = new Image();
_img.src = "image/myImgTest.png";
var _url;
_img.onload = function() {
DrawScreen(); // just some process: drawing image
_url = _canvas.toDataURL();
alert("test"); **// this alert is printed on FF not on Chrome ???**
// window.location = url; **// With this command on FF, I show my Image**
document.write("<img src='"+url+"' >"); **// on FF, I show my image but when I would like to see the source code on my current page, there is nothing just blank ?? And on Chrome, I never show my image.**
**// In fact, I am expected to generate something like this: <img src="data:image/png;base64,iVBORw0KGgo....."> at this place **
};
function DrawScreen() {
// my process
}
</script>
</body>
</html>
* //事实上,我希望生成这样的东西:在这个地方*
答案 0 :(得分:0)
当您“在本地PC上工作”时...您是否在本地PC上有网络服务器,或者您只是直接从硬盘驱动器打开HTML文件?
您可能希望将.src
的分配移至.onload
事件处理程序之后,否则.onload
可能永远不会被触发。
var _img = new Image();
var _url;
_img.onload = function() {
...
};
_img.src = "image/myImgTest.png";