您能告诉我如何从MSACCESS表中名为IMGFAM的字段(类型oleobject)中检索图像到运行时图片框中的一组(很多作为表中的记录)。
我可以显示按钮但我不能用从该字段获得的图片(jpg)来做。谢谢你的帮助。
P.S:我使用过MS Access 2007和VB.net 2008 express。
答案 0 :(得分:2)
在您想要将图像操作到db Access之前,您必须知道IO.MemoryStream的基本类。以下来自vb论坛http://www.vbforums.com/showthread.php?489787-02-03-Loading-JPG-images-from-Access-to-VB.Net
的示例代码Imports System.Data.OleDb
Imports System.IO
Public Class Form1
Private connection As New OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=|DataDirectory|\db1.mdb;User Id=admin;Password=;")
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Me.PictureBox1.Image = Image.FromFile(Path.Combine(Application.StartupPath, "Properties.jpg"))
End Sub
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Try
Dim stream As New IO.MemoryStream
Me.PictureBox1.Image.Save(stream, Imaging.ImageFormat.Jpeg)
Dim command As New OleDbCommand("INSERT INTO Table1 (Picture) VALUES (@Picture)", connection)
command.Parameters.AddWithValue("@Picture", stream.GetBuffer())
connection.Open()
command.ExecuteNonQuery()
connection.Close()
command.Dispose()
stream.Dispose()
Catch ex As Exception
MessageBox.Show(ex.ToString())
End Try
End Sub
Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
Try
Dim command As New OleDbCommand("SELECT Picture FROM Table1 WHERE ID = @ID", connection)
Me.connection.Open()
command.Parameters.AddWithValue("@ID", Me.GetGreatestID())
Dim pictureData As Byte() = DirectCast(command.ExecuteScalar(), Byte())
connection.Close()
command.Dispose()
Dim stream As New IO.MemoryStream(pictureData)
Me.PictureBox2.Image = Image.FromStream(stream)
stream.Dispose()
Catch ex As Exception
MessageBox.Show(ex.ToString())
End Try
End Sub
答案 1 :(得分:0)
Dim OpenFileDialog1 As New OpenFileDialog
With OpenFileDialog1
.CheckFileExists = True
.ShowReadOnly = False
.Filter = "All Files|*.*|Bitmap Files (*)|*.bmp;*.gif;*.jpg"
.FilterIndex = 2
If .ShowDialog = DialogResult.OK Then
' Load the specified file into a PictureBox control.
pbNewImage.Image = Image.FromFile(.FileName)
End If
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