Question

我是新手所以如果我忽略了一些基本的东西，请耐心等待我，但我正在努力为我朋友的瑜伽工作室制作瑜伽课程，其概念应该是这样的：

Monday

Dynamic Yoga with Mary 6pm

Soft yoga with Susie 8pm

Wednesday

Hatha yoga with Bob 5pm

Hot yoga with Alice 7pm

所以我想获取课程列表，然后看星期一是否有瑜伽课。如果有的话，我会在列表和所有星期一课程中添加“星期一”，依此类推其他所有日期。

问题：

到目前为止，我的代码附加了瑜伽课程的所有日期，但随后将所有课程从一周添加到每一天，此时他们应该只添加与每天相对应的课程。

即。什么时候应该：

Monday_list = [Monday, [[Class1Monday],[Class2Monday]]

相反：

Monday_list [Monday, [[CLass1Monday],[CLass2Monday],[CLass1Tuesday],[CLass2Tuesday]]]

这是我的代码（它在Google App Engine上，可以解释代码中的一些奇怪内容......）：

def get_classes():
    weekly_classes = []
    d = {1: 'Monday', 
         2: 'Tuesday', 
         3: 'Wednesday', 
         4: 'Thursday', 
         5: 'Friday', 
         6: 'Saturday', 
         7: 'Sunday'}
    yoga_classes = Schema.all() #appengine DB request
    if yoga_classes:
         #list that will be sent to template
        for n in range(1,8):
            day_classes = []
            for e in yoga_classes:
                if e.weekday == n:
                    day = d[n]
                    class_output = [str(e.name),
                                    str(e.teacher),
                                    str(e.description)
                                    ]
                day_classes.append(class_output)
            day_output = [day,day_classes]
            weekly_classes.append(day_output)
        self.response.out.write(weekly_classes)

Answer 1

这里有一些pythonic代码，利用itertools。数据按groupby()的要求按日排序，然后进行分组。我发现使用range函数表明你正在做的事情比Cthon更多，而且可能有一种更简洁的方法。请注意，绝大多数此代码只是设置要处理的虚拟数据。

class Yoga():
    def __init__(self,weekday,name,teacher,description):
        self.weekday=weekday
        self.name=name
        self.teacher=teacher
        self.description=description
    def __str__(self):
        return "%s yoga with %s %s" % (self.name,self.teacher,self.description)
    def __repr__(self):
        return str(self)

# just make up some data to work with
yoga_classes = (Yoga(1,"dynamic","mary","6pm"),
                Yoga(1,"soft","susie","8pm"),
                Yoga(3,"hatha","bob","5pm"),
                Yoga(3,"hot","alice","7pm"))

daylookup = (None,"Monday","Tuesday","Wednesday",
            "Thursday","Friday","Saturday","Sunday")

import itertools
def get_classes():
    weekly_classes = []
    ycsorted = sorted(yoga_classes,key=lambda x: x.weekday)
    for k,g in itertools.groupby(ycsorted,key=lambda x: x.weekday):
        weekly_classes.append((daylookup[k],tuple(g)))
    return weekly_classes

import pprint
pprint.pprint(get_classes())

创建嵌套列表的问题

1 个答案: