调用堆栈仅显示第三方库

Question

在我的程序崩溃时，Visual Studio给了我下面的调用堆栈，它没有对我编写的任何代码或者源代码中的任何代码的引用，这是否表明OpenCV库中存在错误？

我认为仍然可以在我的程序中找到触发崩溃的源操作/函数，通常就是这种情况。

    opencv_imgproc243d.dll!cv::RGB2RGB<unsigned char>::operator()(const unsigned char * src=0x00000000, unsigned char * dst=0x0f010050, int n=1920)  Line 208 + 0x6 bytes   C++
>   opencv_imgproc243d.dll!cv::CvtColorLoop_Invoker<cv::RGB2RGB<unsigned char> >::operator()(const cv::Range & range={...})  Line 176 + 0x1d bytes  C++
    opencv_core243d.dll!`anonymous namespace'::ParallelLoopBodyWrapper::operator()(const cv::Range & sr={...})  Line 134 + 0x17 bytes   C++
    opencv_core243d.dll!`anonymous namespace'::ProxyLoopBody::operator()(int i=0)  Line 177 C++
    opencv_core243d.dll!Concurrency::_Parallel_chunk_helper_invoke<int,unsigned int,`anonymous namespace'::ProxyLoopBody,0>::_Invoke(const int & _First=0, unsigned int & _Index=0, const `anonymous-namespace'::ProxyLoopBody & _Func={...})  Line 1445    C++
    opencv_core243d.dll!Concurrency::_Parallel_chunk_helper<int,unsigned int,`anonymous namespace'::ProxyLoopBody,0>::operator()()  Line 1833 + 0x16 bytes  C++
    opencv_core243d.dll!Concurrency::task_handle<Concurrency::_Parallel_chunk_helper<int,unsigned int,`anonymous namespace'::ProxyLoopBody,0> >::operator()()  Line 116 C++
    opencv_core243d.dll!Concurrency::details::_UnrealizedChore::_InvokeBridge<Concurrency::task_handle<Concurrency::_Parallel_chunk_helper<int,unsigned int,`anonymous namespace'::ProxyLoopBody,0> > >(Concurrency::task_handle<Concurrency::_Parallel_chunk_helper<int,unsigned int,`anonymous namespace'::ProxyLoopBody,0> > * _PChore=0x036fb148 {_M_first=0 _M_step=1 _M_function={...} ...})  Line 3495   C++
    msvcr100d.dll!Concurrency::details::_UnrealizedChore::_StructuredChoreWrapper(Concurrency::details::_UnrealizedChore * pChore=0x036fb148 {_M_first=0 _M_step=1 _M_function={...} ...})  Line 99 + 0xc bytes C++
    msvcr100d.dll!Concurrency::details::_UnrealizedChore::_Invoke()  Line 3454 + 0xc bytes  C++
    msvcr100d.dll!Concurrency::details::WorkItem::Invoke()  Line 75 C++
    msvcr100d.dll!Concurrency::details::InternalContextBase::ExecuteChoreInline(Concurrency::details::WorkItem * pWork=0x0fb8f7dc)  Line 1385   C++
    msvcr100d.dll!Concurrency::details::InternalContextBase::Dispatch(Concurrency::DispatchState * pDispatchState=0x0fb8f7fc)  Line 1478    C++
    msvcr100d.dll!Concurrency::details::FreeThreadProxy::Dispatch()  Line 157   C++
    msvcr100d.dll!Concurrency::details::ThreadProxy::ThreadProxyMain(void * lpParameter=0x029c2160)  Line 162   C++
    kernel32.dll!@BaseThreadInitThunk@12()  + 0x12 bytes    
    ntdll.dll!___RtlUserThreadStart@8()  + 0x27 bytes   
    ntdll.dll!__RtlUserThreadStart@8()  + 0x1b bytes    

由于函数接收到已损坏的Mat，因此在崩溃时将其输出到控制台，因此看起来断言失败。

Answer 1

我猜想在你的代码中调用方法cvtColor（）时opencv会在自己的线程中运行它。

您可以看到opencv源here，它显示在Color.cpp文件中调用此方法。

RGB2RGB格式类似于从一个色彩空间转换到另一个色彩空间时使用的格式，我猜这可能是创建一个副本。

因此，我可能会在您的代码中查找以下命令作为原因。

cvtColor(src, dst, CV_RGB2RGB);
or 
Mat A = Mat(...);
Mat B = A.clone();

I don't think this will cause it as this just copies header information.
Mat B(A);

or

A.copyTo(B);

您可以排除Mat将您转换为BGR或GRAY的位置。事实上，正如我所理解的那样，opencv在BGR色彩空间中工作，你很可能已经将Mat转换为RGB，这可能是一个很好的搜索起点。

修改

断言还表明你试图将一个空的Mat克隆（）给另一个。

Asset(   y==0   )

如果只是偶尔发生这种情况，那么我会查找if（）语句，或者发生克隆或转换的条件情况。