Question

假设我们有一个Driver模型，而Driver可能拥有很多车。我希望能够过滤QuerySet，以便能够看到驾驶特定车辆的所有司机。即：

class Driver(models.Model):
    primary_car = models.ForeignKey(Car, related_name='primary')
    cars = models.ManyToMany(Car, related_name = 'all')

    def save(self, force_insert=False, force_update=False, using=None, *args, **kwargs):
        if self.primary_car not in self.cars.all():
            self.cars.add(self.primary_car)
        super(Car, self).save(force_insert=False, force_update=False, using=None, *args, **kwargs)

class Car(models.Models):
    name = models.CharField(max_length=30)

所以，假设我有50名司机，而且我知道7名有Yugos，而2名有Yugos作为他们的主要赛车。如何搜索这些驱动程序？我认为只需不到2分钟的谷歌搜索即可找到这个答案，所以我可能会遗漏一些基本的东西。

更新：我修复了损坏的save()方法

Answer 1

from django.db.models import Q

# drivers who have either have a "Yugo" as their primary car,
# or have a relation to one
yugo_drivers = Driver.objects.filter(Q(primary_car__name__iexact="Yugo") | 
                                     Q(cars__name__iexact="Yugo"))

有两件事可以帮助你：

Answer 2

qs = Driver.objects.filter(Car_name=your_car.name)

Django按可能在多对多字段中的值进行过滤

2 个答案: