我真的迷路了。
为什么我为每个UIImage
获得两次NSLog?
//------ get the images from the camera roll ----------
assets=[[NSMutableArray alloc]init];
NSMutableArray *cameraRollPictures=[[NSMutableArray alloc]init];
ALAssetsLibrary *assetsLibrary = [[ALAssetsLibrary alloc] init];
[assetsLibrary enumerateGroupsWithTypes:ALAssetsGroupSavedPhotos usingBlock:^(ALAssetsGroup *group, BOOL *stop)
{
NSInteger numberOfAssets = [group numberOfAssets];
NSLog(@"NUM OF IMAGES:%d",numberOfAssets);
if (numberOfAssets > 0)
{
for (int i = 0; i <= numberOfAssets-1; i++)
{
[group enumerateAssetsAtIndexes:[NSIndexSet indexSetWithIndex:i] options:0 usingBlock:^(ALAsset *result, NSUInteger index, BOOL *stop)
{
UIImage *thumbnail = [UIImage imageWithCGImage:[result thumbnail]];
[assets addObject:thumbnail];
NSLog(@"theObject!!!! -- (%d) %@",i,thumbnail);
//******* for each i its here twice !! ********
}];
}
}
答案 0 :(得分:6)
出于某种原因,enumerateAssetsAtIndexes
(和enumerateAssetsUsingBlock
)在枚举结束时使用result == nil
和index == NSNotFound
对块进行额外调用。如果将NSLog()更改为
NSLog(@"i=%d, index=%ld, result=%@", i, (unsigned long)index, result);
然后你会得到输出
NUM OF IMAGES:2
i=0, index=0, result=ALAsset - Type:Photo, URLs:assets-library://asset/asset.PNG?id=...
i=0, index=2147483647, result=(null)
i=1, index=1, result=ALAsset - Type:Photo, URLs:assets-library://asset/asset.PNG?id=...
i=1, index=2147483647, result=(null)
因此,您必须检查result
的值并忽略nil
值:
for (int i = 0; i <= numberOfAssets-1; i++) {
[group enumerateAssetsAtIndexes:[NSIndexSet indexSetWithIndex:i] options:0 usingBlock:^(ALAsset *result, NSUInteger index, BOOL *stop)
{
if (result != nil) {
UIImage *thumbnail = [UIImage imageWithCGImage:[result thumbnail]];
[assets addObject:thumbnail];
}
}];
}
请注意,您可以将枚举简化为
[group enumerateAssetsUsingBlock:^(ALAsset *result, NSUInteger index, BOOL *stop) {
if (result != nil) {
UIImage *thumbnail = [UIImage imageWithCGImage:[result thumbnail]];
[assets addObject:thumbnail];
}
}];