在BST中更新节点密钥的值

时间:2013-02-26 18:04:32

标签: c++ algorithm binary-search-tree

template <class T>
void BinaryTree<T>::UpdateKey(T newkey,T oldkey)
{
     TreeNode<T> *temp,*temp1,*temp2,*temp3;
     temp=Root;
      //checking to see if the new value clashes with any existing value
     while (temp!=NULL)
     {
         if (temp->key==newkey)
         {
            cout<<"New key already exists in the tree.CannotUpdate!";                  
            cout<<endl;                 
            return;
         }
         if (newkey>temp->key)
         {
            temp=temp->RightChild;
         }
         else if (newkey<temp->key)
         {
            temp=temp->LeftChild;
         }
     }

     temp=Root;                                  
     while (temp!=NULL)
     {      
         if (temp->key==oldkey)
         {
             temp1=temp->Parent;
             temp->key=newkey;
             if (temp1->LeftChild==temp)  //if the node is the left child of its parent
             {
                 if (temp1->key<temp->key)
                 {
                     //move to right child of node whose key has to be changed and  
                    //then keep on moving to the LeftChild of every node until last 
                     //node is reached and exchange the key/value 
                     temp=temp->RightChild;                     
                     while (temp->LeftChild!=NULL)
                     {
                         temp=temp->LeftChild;
                     }
                     //exchanging key/value of the two nodes
                     temp2=temp;
                     temp3=temp1->LeftChild;
                     temp->key=temp3->key;
                     temp->value=temp3->value;
                     temp3->key=temp2->key;
                     temp3->value=temp2->value;
                 }
                 cout<<"Value updated successfully1"<<endl;
                 return;
             }
             //if the node is right child of its parent
             else if (temp1->RightChild==temp)
             {
                   //if key of parent is greater than its right child
                  if (temp1->key>temp->key)
                  {
                  //move to the leftchild of the node whose value has to change
                  //and then keep moving to right child until the last node
                      temp=temp->LeftChild;
                      while (temp->RightChild!=NULL)
                      {
                          temp=temp->RightChild;
                      }
                     //exchange value/key of the last node with the node whose value
                      //is updated
                      temp2=temp;
                      temp3=temp1->RightChild;
                      temp->key=temp3->key;
                      temp->value=temp3->value;
                      temp3->key=temp2->key;
                      temp3->value=temp2->value;                  
                  }     
                  cout<<"Value updated successfully2<<endl;
                                                                                                             return;     
             }                  
             //comparing newkey with the left child to see if its less than the latter
             if (temp->LeftChild!=NULL && newkey<(temp->LeftChild)->key)
             {

                 temp->key=newkey;                 
                 temp1=temp;        
                 temp=temp->LeftChild;
                 while (temp->RightChild!=NULL)
                 {
                     temp=temp->RightChild;
                 }           
                 temp2=temp1;                            
                 temp1->key=temp->key;
                 temp1->value=temp->value;
                 temp->key=temp2->key;
                 temp->value=temp2->value;

                 cout<<"Value updated successfully3"<<endl;
                 return;
             }
             //comparing with the right child if it is greater than the latter
             //and moving key/value to the right spot if condition is met
             else if (temp->RightChild!=NULL && newkey>(temp->RightChild)->key)
             {
                 temp->key=newkey;
                 temp1=temp;
                 while (temp->LeftChild!=NULL)
                 {
                     temp=temp->LeftChild;
                 }
                 temp2=temp1;                            
                 temp1->key=temp->key;
                 temp1->value=temp->value;
                 temp->key=temp2->key;
                 temp->value=temp2->value; 

                cout<<"Value updated successfully4"<<endl;
                return;
             }

         }
         //traversing the tree by comparing oldkey with node key and going in the right
         //direction
         if (oldkey<temp->key)
             temp=temp->LeftChild;
         else if (oldkey>temp->key)
            temp=temp->RightChild;    
     }
}

我使用一个字符串后跟一个数字来构建BST树,因此节点有一个键/值对。问题是当我更新节点时(即更改节点的键并重新排列节点,以便它在树上的正确位置),它没有正确地给它那个键,因为当我搜索该键(使用搜索功能;我的搜索功能工作正常,我已经彻底测试了),我在树中没有匹配的密钥。我已经为其他一些功能提供了帮助,可以在这里找到它们:
Binary Search Tree--delete function not working

0 个答案:

没有答案