Question

我编写了以下查询，但它没有在日期上正确分组并返回2行，实际上应该由GROUP BY组合成一行。

select i.overridedate,
       month(i.Overridedate), 
       count(i.id)as count,
       sum(case when oi.rating <50 then 1 else 0 end) as unfav,
       sum(case when oi.Rating =50  then 1 else 0 end) as neu,
       sum(case when oi.Rating >50  then 1 else 0 end) as fav,
       avg(oi.Rating)as 'Av Rating'
from Items i (nolock)

inner join ItemOrganisations oi (nolock) on i.ID= oi.ItemID
inner join Lookup_ItemTypes it (nolock) on it.ID = i.ItemTypeID
inner join Batches b (nolock) on b.ID=i.BatchID
inner join Lookup_ItemStatus lis (nolock) on lis.ID = i.StatusID
inner join Lookup_BatchStatus lbs (nolock) on lbs.ID = b.StatusID
inner join Lookup_BatchTypes bt on bt.id = b.Typeid

where lbs.Name = 'Completed by Analyst'
      or lbs.Name='Delivered/Imported into Neptune Online'
      and lis.Name = 'Complete'
      and i.IsRelevant = 1
      and bt.Name = 'Live'
    group by i.overridedate, Month(i.OverrideDate)
    having i.OverrideDate between '2012-07-01 00:00:00.000' and '2012-09-30 00:00:00.000'

如您所见，代表第7个月数据的最后两行未按以下方式分组：

NULL       NULL             1     0     1     0     1     55
2013-01-03 00:00:00.000     1     1     1     0     0     10
2012-05-28 00:00:00.000     5     7     1     0     1     50
2012-06-01 00:00:00.000     6     7     1     0     0     20
2012-07-10 00:00:00.000     7     1     0     0     0     NULL
2012-07-11 00:00:00.000     7     8     1     0     6     66

Answer 1

group by是正确的。为什么要在其中包含覆盖日期？

也许您的选择应该是：

select min(i.overridedate), month(i.Overridedate),
. . . 
group by month(i.Overridedate)

并且，我非常同意包含年份的评论：

select min(i.overridedate), year(i.Overridedate), month(i.Overridedate),
. . . 
group by year(i.Overridedate), month(i.Overridedate)

GROUP BY返回错误的值？

1 个答案: