选择一个表中只有一个值的行

时间:2013-02-26 16:10:05

标签: mysql sql select

这是我的表格:

(我之前没有说过,colum2是字符串类型,不是整数,对不起)

╔══════╦═══════╗
║ USER ║ COLOR ║
╠══════╬═══════╣
║ a    ║ Red   ║
║ b    ║ Blue  ║
║ c    ║ Blue  ║
║ b    ║ Red   ║
║ a    ║ Red   ║
║ c    ║ White ║
╚══════╩═══════╝

我只需要独占 color =“Red”的行。
它必须返回“a”(“b”也包含值“Blue”)。

如何设置选择?谢谢和问候

3 个答案:

答案 0 :(得分:3)

SELECT  column1
FROM    TableName
GROUP   BY Column1
HAVING  COUNT(DISTINCT column2) = 1
        AND MAX(column2) = 1

这是另一种方式,

SELECT  column1
FROM    TableName
GROUP   BY Column1
HAVING  MAX(column2) = MIN(column2) AND
        MAX(column2) = 1

更新1

SELECT  user
FROM    TableName
GROUP   BY user
HAVING  SUM(color = 'red') = COUNT(*)

答案 1 :(得分:0)

更有效的方法是比较minmax值:

select column1
from t
group by column1
having min(column2) = max(column2) and min(column2) = 1

如果列可以采用NULL值,则还需要排除这些值:

select column1
from t
group by column1
having min(column2) = max(column2) and min(column2) = 1 and count(column2) = count(*)

答案 2 :(得分:-1)

Select distinct Column1 from Table1 Where Column2='1'

如果它是整数,那么:

Select distinct Column1 from Table1 Where Column2=1

假设Table1是表名