如何将两个字符串转换为perl中的哈希?

时间:2013-02-26 13:53:20

标签: string perl hash map split

我有两个字符串:

my $wTime = "00:00-06:00 / 06:00-09:00 / 09:00-17:00 / 17:00-23:00 / 23:00-00:00";
my $wTemp = "17.0 °C / 21.0 °C / 17.0 °C / 21.0 °C / 17.0 °C";

我想将这些字符串连接到散列,其中每个时间刻度的第一部分是一个键,例如:

$hash = (
  "00:00" => "17.0 °C",
  "06:00" => "21.0 °C",
  "09:00" => "17.0 °C",
  "17:00" => "21.0 °C",
  "23:00" => "17.0 °C"
);

我尝试了一些地图和分裂的变体,但我有一些神秘的结果; - )

%hash = map {split /\s*\/\s*/, $_ } split /-/, $wTime;

4 个答案:

答案 0 :(得分:2)

您可以使用List::MoreUtils zip / mesh function

my @time_ranges = split ' / ', $wTime;
my @times = map { (split '-', $_)[0] } @time_ranges;
my @temps = split ' / ', $wTemp;

use List::MoreUtils qw(zip);
my %hash = zip @times, @temps;

答案 1 :(得分:2)

还有一种方法:

my $wTime = "00:00-06:00 / 06:00-09:00 / 09:00-17:00 / 17:00-23:00 / 23:00-00:00";
my $wTemp = "17.0 °C / 21.0 °C / 17.0 °C / 21.0 °C / 17.0 °C";

my %h1;
@h1{$wTime=~/([\d:]+)-/g}=split(m! / !,$wTemp);

答案 2 :(得分:1)

这是一个没有List :: MoreUtils的详细解决方案。

my $wTime = "00:00-06:00 / 06:00-09:00 / 09:00-17:00 / 17:00-23:00 / 23:00-00:00";
my $wTemp = "17.0 °C / 21.0 °C / 17.0 °C / 21.0 °C / 17.0 °C";

my @time = map { (split /-/, $_)[0] } split m! / !, $wTime;
my @temp = split m! / !, $wTemp;

my %hash;
for (my $i=0; $i <= $#time; $i++) { # Iterate the times via their index...
  # This only works if we have an equal number of temps and times of course.
  $hash{$time[$i]} = $temp[$i];
}

答案 3 :(得分:1)

创建两个列表。

my @wTimes = map /([^-]+)/, split qr{ / }, $wTime;
my @wTemps = split qr{ / }, $wTemp;

然后使用哈希切片。

my %hash;
@hash{@wTimes} = @wTemps;