ExecuteNonQuery导致参数映射错误

时间:2013-02-26 13:31:42

标签: c# ado.net

您好我正在尝试使用ADO.NET将数据插入数据库。这是我的代码。 这是我的C#代码:

 public void CreateBook(FormCollection collection)
        {
            string name = collection["BookName"];
            string author = collection["Author"];
            string description = collection["Description"];
            int category = int.Parse(collection["category"]);
            DateTime currentDate = new DateTime();

            using (SqlConnection connection = new SqlConnection(connectionString)) {
                connection.Open();
                SqlCommand command = new SqlCommand("AddBook", connection);
                command.CommandType = CommandType.StoredProcedure;
                command.Parameters.Add(createParameter(name, "@Name"));
                command.Parameters.Add(createParameter(author, "@Author"));
                command.Parameters.Add(createParameter(description, "@Description"));
                command.Parameters.Add(createParameter(currentDate.Date, "@Date"));
                command.Parameters.Add(createParameter(category, "@CategoryId"));
                command.ExecuteNonQuery();
            }
        }
        //there are 2 other overloads of this method
        private SqlParameter createParameter(string parameter , string parameterName) {
            SqlParameter param = new SqlParameter();
            param.ParameterName = parameterName;
            param.Value = param;
            return param;
        }

这是我的SQL代码:

 CREATE PROCEDURE [dbo].[AddBook]
    @Name nvarchar(MAX),
    @Author nvarchar(MAX),
    @Description nvarchar(MAX),
    @Date date  ,
    @CategoryId int
 AS
    INSERT INTO Books (Name , Author , Description , PublicationDate , CategoryId)
    VALUES (@Name , @Author , @Description , @Date , @CategoryId)

当触发ExecuteNonQueryuery时,我收到此错误:

No mapping exists from object type System.Data.SqlClient.SqlParameter to a known managed provider native type. 

我做错了什么?

2 个答案:

答案 0 :(得分:5)

我怀疑这一行是最直接的问题:

param.Value = param;

你的意思是:

param.Value = parameter;

否则你试图将参数 value 设置为参数本身,这是没有意义的。

但是,我个人建议同样指定类型等。你可以摆脱其他方法,只需使用这样的调用:

command.Parameters.Add("@Name", SqlDbType.NVarChar).Value = name;
command.Parameters.Add("@Date", SqlDbType.DateTime).Value = currentDate.Date;
// etc

答案 1 :(得分:2)

您要将实际参数分配给参数 - param.Value = param;