如何解决json请求中的错误?

时间:2013-02-26 12:50:57

标签: android json request

我需要发送请求,但是在字符串上 url = "http://some-site.com/api/?photos.getPhotosByCategory={"id":"1","limitOne":"3","limitTwo":"3"}";我有Syntax error on tokens, delete these tokens,问题在于引号...请告诉我,我该如何解决?

    url = "http://some-site.com/api/?photos.getPhotosByCategory={"id":"1","limitOne":"3","limitTwo":"3"}";
    new Thread(new Runnable() { 
        public void run(){

            HttpParams myParams = new BasicHttpParams();
            HttpConnectionParams.setConnectionTimeout(myParams, 10000);
            HttpConnectionParams.setSoTimeout(myParams, 10000);
            HttpClient httpclient = new DefaultHttpClient();

            String json=obj.toString();

            try {

                httppost = new HttpPost(url.toString());
                httppost.setHeader("Content-type", "application/json");

                StringEntity se = new StringEntity(obj.toString()); 
                se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
                httppost.setEntity(se); 

                HttpResponse response = httpclient.execute(httppost);
                String temp = EntityUtils.toString(response.getEntity());
                Log.i("tag", temp);


            } catch (ClientProtocolException e) {

            } catch (IOException e) {
            }

                        tw = (TextView)findViewById(R.id.textView1);

                        tw.setText( response.toString());

            tw.post(new Runnable() {
                public void run() {
                    tw = (TextView)findViewById(R.id.textView1);
                    tw.setText( response.toString());
                }
            });

        }
}).start();

}

3 个答案:

答案 0 :(得分:0)

好吧,只需替换你的“by”:

url = "http://some-site.com/api/?photos.getPhotosByCategory={\"id\":\"1\",\"limitOne\":\"3\",\"limitTwo\":\"3\"}";

你可以自己想出来......

答案 1 :(得分:0)

逃避你的报价。请尝试下面的代码

String url = "http://some-site.com/api/?photos.getPhotosByCategory={\"id\":\"1\",\"limitOne\":\"3\",\"limitTwo\":\"3\"}";

答案 2 :(得分:0)

如果您在字符串中遇到问题

url = "http://some-site.com/api/?photos.getPhotosByCategory=`{"id":"1","limitOne":"3","limitTwo":"3"}";`

换到

url = "http://some-site.com/api/?photos.getPhotosByCategory={\"id\":\"1\",\"limitOne\":\"3\",\"limitTwo\":\"3\"}";

如果在服务器上发送此JSON时遇到问题,请使用unicode

http://some-site.com/api/?photos.getPhotosByCategory=%7B%22id%22%3A%221%22%2C%22limitOne%22%3A%223%22%2C%22limitTwo%22%3A%223%22%7D
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