我首先要说这是我在VBForums的第一篇文章,我已经潜伏了一段时间。我是VB的新手,我只是学习它来完成我的论文。所以请原谅我的无知。
我要做的是从另一个程序生成的日志文件中读取数据。我需要从该文件中的特定行进入VB以用于其他算法。此日志文件将不断更新,因此如果可能,它需要是实时读取。
如果重要,则从与另一软件通信的USB设备生成日志文件。
以下是日志示例:
`
08:57:00.932 COM12
08:57:00.935 COM11
08:57:00.935 COM10
08:57:00.936 COM9
08:57:00.936 COM8
08:57:00.937 COM7
08:57:00.938 COM6
08:57:00.939 COM5
08:57:00.939 COM4
08:57:00.998 --> 0108000304FF0000
08:57:01.007 <-- 0108000304FF0000
TRF7970A EVM
08:57:01.014 **** COM Port found! ****
08:57:05.009 --> 010A0003041001210000
08:57:05.009 COM4
08:57:05.173 <-- 010A0003041001210000
Register write request.
08:57:05.173 --> 010C00030410002101020000
08:57:05.280 <-- 010C00030410002101020000
Register write request.
08:57:05.280 --> 010B000304140601000000
08:57:05.715 <-- 010B000304140601000000
ISO 15693 Inventory request.
[,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40]D
08:57:05.716 --> 010A0003041001210000
08:57:05.822 <-- 010A0003041001210000
Register write request.
08:57:05.822 --> 010C00030410002101020000
08:57:05.929 <-- 010C00030410002101020000
Register write request.
08:57:05.929 --> 010B000304140601000000
08:57:06.364 <-- 010B000304140601000000
ISO 15693 Inventory request.
[,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40]D
08:57:06.365 --> 010A0003041001210000
08:57:06.470 <-- 010A0003041001210000
Register write request.
08:57:06.470 --> 010C00030410002101020000
08:57:06.576 <-- 010C00030410002101020000
Register write request.
08:57:06.576 --> 010B000304140601000000
08:57:07.011 <-- 010B000304140601000000
ISO 15693 Inventory request.
[,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40]D
08:57:07.012 --> 010A0003041001210000
08:57:07.117 <-- 010A0003041001210000
Register write request.
08:57:07.117 --> 010C00030410002101020000
08:57:07.223 <-- 010C00030410002101020000
Register write request.
08:57:07.223 --> 010B000304140601000000
08:57:07.658 <-- 010B000304140601000000
ISO 15693 Inventory request.
[,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40]D
08:57:07.659 --> 010A0003041001210000
08:57:07.764 <-- 010A0003041001210000
Register write request.
08:57:07.764 --> 010C00030410002101020000
08:57:07.870 <-- 010C00030410002101020000
Register write request.
08:57:07.870 --> 010B000304140601000000
08:57:08.305 <-- 010B000304140601000000
ISO 15693 Inventory request.
[,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40]D
08:57:08.306 --> 010A0003041001210000
08:57:08.411 <-- 010A0003041001210000
Register write request.
08:57:08.411 --> 010C00030410002101020000
08:57:08.517 <-- 010C00030410002101020000
Register write request.
08:57:08.517 --> 010B000304140601000000
08:57:08.952 <-- 010B000304140601000000
ISO 15693 Inventory request.
[,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40]D
08:57:08.952 --> 010A0003041001210000
08:57:09.058 <-- 010A0003041001210000
Register write request.
08:57:09.058 --> 010C00030410002101020000
08:57:09.164 <-- 010C00030410002101020000
Register write request.
08:57:09.164 --> 010B000304140601000000
08:57:09.585 <-- 010B000304140601000000
ISO 15693 Inventory request.
[,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40]
[AD87851A000007E0,7F]
[,40][,40]D
08:57:09.586 --> 010A0003041001210000
08:57:09.692 <-- 010A0003041001210000
Register write request.
08:57:09.692 --> 010C00030410002101020000
08:57:09.798 <-- 010C00030410002101020000
Register write request.
08:57:09.798 --> 010B000304140601000000
08:57:10.233 <-- 010B000304140601000000
ISO 15693 Inventory request.
[,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40][,40]D
08:57:10.234 --> 010A0003041001210000
08:57:10.340 <-- 010A0003041001210000
Register write request.
08:57:10.340 --> 010C00030410002101020000
08:57:10.446 <-- 010C00030410002101020000
Register write request.
`
我需要能够获得这条线: [AD87851A000007E0,7F]
只是“AD87851A000007E0”然后能够在VB中使用该字符串。这是一个会改变的十六进制代码。
我能够从日志文件中读取,但不能生成有效的输出。
以下是我一直在尝试使用的代码:
Function ReadData(ByRef keyword As String) As IEnumerable(Of String)
Dim result = New List(Of String)
Using reader = New StreamReader("C:\rfid-reader.log")
Dim line As String = reader.ReadLine()
Dim take = False
Do While line IsNot Nothing
If line.StartsWith("[") Then
take = False
End If
If String.Equals("[" + keyword + ",", line) Then
take = True
End If
If take And Not String.IsNullOrEmpty(line) And Not line.StartsWith("'") Then
result.Add(line)
End If
line = reader.ReadLine()
Label1.Text = line
Loop
End Using
Return result
End Function
说实话,我不确定代码是否无效或者我是否只是在将字符串从函数中取出时做错了什么?该函数是否会按原样打印到Label1.Text?
我也试过调用这个函数:
Dim items = ReadData("AD87851A000007E0")
Label1.Text = Convert.ToString(items)
这导致Label1.Text变为“System.Collections.Generic.List`1 [System.String]”
Imports System.IO
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim items = ReadData("AD87851A000007E0")
Label1.Text = String.Join(Environment.NewLine, items)
End Sub
Function ReadData(ByRef keyword As String) As IEnumerable(Of String)
Dim result = New List(Of String)
Using reader = New StreamReader("C:\rfid-reader.log")
Dim line As String = reader.ReadLine()
Dim take = False
Do While line IsNot Nothing
take = False ' resetting take = false to avoide printing all lines
If line.StartsWith("[" + keyword + ",") Then
take = True
End If
If take And Not String.IsNullOrEmpty(line) And Not line.StartsWith("'") Then
result.Add(line)
End If
line = reader.ReadLine()
Loop
End Using
Return result
End Function
结束班
编辑2_ _ __ _ __ _ __ _ __ _ __ _ __ _ __ _ __ _ __ _ __ _ __ _ __ _ __ _ __ _ ___
迄今为止的新代码:
Imports System.IO
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim items = ReadData("AD87851A000007E0") ' Calling the specific hex code from the function. Advancement needed to get ALL hex codes.
' Dim items1 As String = Convert.ToString(items)
' Dim items2 As String = ""
' Dim k As Long
' k = InStrRev(items, ",")
' If k > 0 Then items2 = Left$(items, k)
Label1.Text = String.Join(Environment.NewLine, items) 'Printing function result to Label1
End Sub
'Function to search log file for a specific hex code. Removes not needed portions of the string. Advancements needed:
'Find ALL hex codes
'Ignore repeats until a reset is set true
'Store each hex code found in it's own variable for use in algorithms
Function ReadData(ByRef keyword As String) As IEnumerable(Of String)
Dim result = New List(Of String)
Using reader = New StreamReader("C:\rfid-reader.log")
Dim line As String = reader.ReadLine()
Dim take = False
Do While line IsNot Nothing
take = False ' resetting take = false to avoide printing all lines
If line.StartsWith("[" + keyword + ",") Then
take = True
End If
If take And Not String.IsNullOrEmpty(line) And Not line.StartsWith("'") Then
line = line.Remove(0, 1) 'removing the extra parts of the line
line = line.Remove(16, 4)
result.Add(line) 'adding the valid result
End If
line = reader.ReadLine()
Loop
End Using
Return result
End Function
结束班
Imports System.IO
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim items = ReadData("[") ' Calling the specific hex code from the function. Advancement needed to get ALL hex codes.
Label1.Text = String.Join(Environment.NewLine, items) 'Printing function result to Label1
End Sub
'Function to search log file for a specific hex code. Removes not needed portions of the string. Advancements needed:
'Find ALL hex codes
'Ignore repeats until a reset is set true
'Store each hex code found in it's own variable for use in algorithms
Function ReadData(ByRef keyword As String) As IEnumerable(Of String)
Dim result = New List(Of String)
Using reader = New StreamReader("C:\rfid-reader.log")
Dim line As String = reader.ReadLine()
Dim line1 As String = "COOKIES"
Dim line2 As String = "COOKIES1"
Dim line3 As String = "COOKIES2"
Dim line4 As String = "COOKIES3"
Dim line5 As String = "COOKIES4"
Dim line6 As String = "COOKIES5"
Dim line7 As String = "COOKIES6"
Dim line8 As String = "COOKIES7"
Dim line1found = False
Dim line2found = False
Dim line3found = False
Dim line4found = False
Dim line5found = False
Dim line6found = False
Dim line7found = False
Dim line8found = False
Dim take = False
Do While line IsNot Nothing
take = False ' resetting take = false to avoide printing all lines
If line.StartsWith(keyword) And Not line.StartsWith("[,4") And Not line.StartsWith("[z,") Then
take = True
End If
If line.Contains(line1) Or line.Contains(line2) Or line.Contains(line3) Or line.Contains(line4) Or line.Contains(line5) Or line.Contains(line6) Or line.Contains(line7) Or line.Contains(line8) Then 'attempting to ignore duplicates
take = False
End If
If take And Not String.IsNullOrEmpty(line) And Not line.StartsWith("'") Then
line = line.Remove(0, 1) 'removing the extra parts of the line
line = line.Remove(16, 4)
result.Add(line) 'adding the valid result
If line1 <> line And Not line1found Then 'assining results to variables for duplicate elimiation
line1 = line
line1found = True
ElseIf line2 <> line And line1 <> line And Not line2found Then
line2 = line
line2found = True
ElseIf line <> line3 And line <> line2 And line1 <> line And Not line3found Then
line3 = line
line3found = True
ElseIf line <> line4 And line <> line3 And line <> line2 And line <> line1 And Not line4found Then
line4 = line
line4found = True
ElseIf line <> line5 And line <> line4 And line <> line3 And line <> line2 And line <> line1 And Not line5found Then
line5 = line
line5found = True
ElseIf line6 <> line And line5 <> line And line4 <> line And line3 <> line And line2 <> line And line1 <> line And Not line6found Then
line6 = line
line6found = True
ElseIf line7 <> line And line6 <> line And line5 <> line And line4 <> line And line3 <> line And line2 <> line And line1 <> line And Not line7found Then
line7 = line
line7found = True
ElseIf line8 <> line And line7 <> line And line6 <> line And line5 <> line And line4 <> line And line3 <> line And line2 <> line And line1 <> line And Not line8found Then
line8 = line
line8found = True
End If
End If
line = reader.ReadLine()
Loop
End Using
Return result
End Function
结束班
答案 0 :(得分:1)
您的代码存在一些问题。第一个问题是您使用的是String.Equals
而不是line.StartsWith
:
If String.Equals("[" + keyword + ",", line) Then
take = True
End If
您会注意到,在上述代码中,如果整行与字符串&#34; [AD87851A000007E0,&#34;完全匹配],则只会设置take = True
。但是你要找的那条线并不等于那个字符串 - 它只是从那个字符串开始。因此,您应该将该代码更改为:
If line.StartsWith("[" + keyword + ",") Then
take = True
End If
接下来,在读取每一行之后,在循环内设置Label1.Text = line
,无论该行是否匹配。你正在做什么会起作用,但可能不是你想要的方式。你现在拥有它的方式,它会用读取的每一个新行覆盖标签的整个文本内容。正如我所说的那样,每一行都是如此,而不仅仅是匹配的那一行。由于你忙于循环,屏幕实际上不会刷新直到你完成,所以最后它只会显示文件的最后一行。
如果您希望它显示所有匹配的行,您需要将其移动到If take...
块内,并且需要将这些行连接在一起,如下所示:
If take And Not String.IsNullOrEmpty(line) And Not line.StartsWith("'") Then
result.Add(line)
Label1.Text = Label1.Text & Environment.NewLine & line
End If
但是,这仍然不是一个好方法。将UI代码与您的业务逻辑混合在一起绝对不是一个好主意,因此您在调用ReadData
后设置标签的直觉是正确的想法。但是,您无法使用Convert.ToString
来显示列表的内容。正如您所知,这只会显示数据类型的名称。为此,您需要将列表中的字符串连接成一个字符串,如下所示:
Label1.Text = String.Join(Environment.NewLine, items)
我使用Environment.NewLine
作为分隔符,但您可以使用任何您想要的分隔符。例如,如果要在一行中显示所有内容,可以使用", "
作为分隔符。
答案 1 :(得分:1)
我迟到了,但这是对Edit 3的修改,以简化一些事情,并创建一个框架,允许您扩展验证线条的方式:
Function readData() As List(Of String)
readData = New List(Of String)
Using reader As New StreamReader("C:\rfid-reader.log")
While Not reader.EndOfStream
For Each line In reader.ReadToEnd.Split(ControlChars.CrLf)
If validLine(line) AndAlso Not readData.Contains(line.Split(",")(0).Substring(1)) Then readData.Add(line.Split(",")(0).Substring(1))
Next
End While
End Using
End Function
Private Function validLine(line As String) As Boolean
validLine = True
'insert criteria to validate the line's format (you could also look at regex)
If Not line.Trim.Length > 0 Then
validLine = False
Exit Function
End If
If Not line.Trim.StartsWith("[") AndAlso line.Trim.EndsWith("]") Then
validLine = False
Exit Function
End If
If Not line.Split(",").Length = 2 Then
validLine = False
Exit Function
End If
If Not line.Split(",")(0).Substring(1).Length > 1 Then
validLine = False
Exit Function
End If
If Not isHex(line.Split(",")(0).Substring(1)) Then
validLine = False
Exit Function
End If
'...
End Function
Private Function isHex(str As String) As Boolean
isHex = True
For i = 0 To str.Length - 1
If Not {"1", "2", "3", "4", "5", "6", "7", "8", "9", "0", "A", "B", "C", "D", "E", "F"}.Contains(str.Substring(i, 1)) Then
isHex = False
Exit Function
End If
Next
End Function