我的Web服务返回一个字符串(xml)am使用DOM构建此字符串现在问题是当我想将此xml转换为String时。最初添加了一个额外的CDATA,我似乎无法将其删除。 我从stackoverflow得到了这个漂亮的函数,但提到的问题是它添加了我不需要的CDATA,因为我想返回一个Xml字符串。 请注意,我没有使用Soap网络服务。
public static String doctoString(Document doc) {
try {
StringWriter sw = new StringWriter();
TransformerFactory tf = TransformerFactory.newInstance();
Transformer transformer = tf.newTransformer();
transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
transformer.setOutputProperty(OutputKeys.METHOD, "xml");
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
transformer.transform(new DOMSource(doc), new StreamResult(sw));
return sw.toString();
} catch (Exception ex) {
throw new RuntimeException("Error converting to String", ex);
}
}
完整输出:
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<ns2:getInvoppResponse xmlns:ns2="http://services.com/">
<return>
<![CDATA[
<users>
<user>
<id>1</id>
<name>sert</name>
</user>
</users>
]]>
</return>
</ns2:getInvoppResponse>
</soap:Body>
</soap:Envelope>
需要身体输出:
<return>
<users>
<user>
<id>1</id>
<name>sert</name>
</user>
</users>
</return>
答案 0 :(得分:0)
对于不太优雅但功能强大的Java解决方案(针对新XML进行了更新):
p = Pattern.compile("\\A.*?(\\<users\\>.*\\<\\/users\\>).*?\\z", Pattern.DOTALL );
s = "<soap:Envelope xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\">\n" +
" <soap:Body>\n" +
" <ns2:getInvoppResponse xmlns:ns2=\"http://services.com/\">\n" +
" <return>\n" +
" <![CDATA[\n" +
" <users>\n" +
" <user>\n" +
" <id>1</id>\n" +
" <name>sert</name>\n" +
" </user>\n" +
" </users>\n" +
" ]]>\n" +
" </return>\n" +
" </ns2:getInvoppResponse>\n" +
" </soap:Body>\n" +
"</soap:Envelope>\n";
Matcher m = p.matcher(s);
if (m.matches())
{
s =m.group(1);
}