我是从数据库输入信息的LINQ。我设置了try.catch块以捕获这些异常。但是我相信我遇到了一个痛处,我试图看看消息是什么,但它只是绕过打印消息给我,直接进入错误页面。这是我到目前为止的代码示例。我很想得到一些关于为什么这似乎表现得如此奇怪的意见。
private void CreateEntry()
{
var date = DateTime.Today;
var version = (from v in house.StayLateVersions
where v.Active
select v).FirstOrDefault();
if (version == null)
{
throw new NullReferenceException();
}
//Try to create an entry for the database. Upon failure, sends the exception to ThrowDbError();
try
{
ResidenceHallInspection rhi = new ResidenceHallInspection();
rhi.versionId = version.id;
rhi.submitDate = DateTime.Now;
rhi.CheckInOrOut = ddlCheck.SelectedItem.Text;
rhi.Id = txtId.Text;
rhi.FirstName = txtFirstName.Text;
rhi.MiddleName = txtMiddleName.Text;
rhi.LastName = txtLastName.Text;
rhi.Walls = chbxWalls.SelectedItem.Text;
rhi.Windows = chbxWindows.SelectedItem.Text;
rhi.Blinds = chbxBlinds.SelectedItem.Text;
rhi.Couch = chbxCouch.SelectedItem.Text;
rhi.CommonRoomCouch = chbxCRCouch.SelectedItem.Text;
rhi.CommonRoomChair = chbxCRChair.SelectedItem.Text;
rhi.Doors = chbxDoors.SelectedItem.Text;
rhi.Carpet = chbxCarpet.SelectedItem.Text;
rhi.Ceiling = chbxCeiling.SelectedItem.Text;
rhi.CommonRoomCounter = chbxCRCounter.SelectedItem.Text;
rhi.Cabinet = chbxCabinet.SelectedItem.Text;
rhi.Phone = chbxPhone.SelectedItem.Text;
rhi.Bed = chbxBed.SelectedItem.Text;
rhi.Desk = chbxDesk.SelectedItem.Text;
rhi.DeskChairs = chbxDeskChair.SelectedItem.Text;
rhi.Tub = chbxTub.SelectedItem.Text;
rhi.Vanity = chbxVanity.SelectedItem.Text;
rhi.Notes = txtNotes.Text;
rhi.Building = txtResHall.Text;
rhi.ApartmentNumber = txtSuitNo.Text;
rhi.BedSpace = txtBedSpace.Text;
house.AddToResidenceHallInspections(rhi);
house.SaveChanges();
}
catch (Exception oe)
{
ThrowDbError(oe);
Response.Write(oe.InnerException);
}
}
/*=================================================*/
/*Possible Errors */
/*=================================================*/
private void ThrowDbError(Exception oe)
{
Response.Write(oe.Source);
house.Dispose();
Session.Contents.Add("FormException", oe);
Response.Redirect("/Database-Error/", true);
}
答案 0 :(得分:0)
最可能的原因是您在try / catch块之外运行数据库version
查询。此数据库访问代码中的任何异常都不会由您在上面显示的代码处理。
尝试扩展您的try
块以包含数据库访问代码:
var version = (from v in house.StayLateVersions
where v.Active
select v).FirstOrDefault();
if (version == null)
{
throw new NullReferenceException();
}
并查看此时是否发现了错误。