Question

我正在尝试编写一个bash函数，如果用户输入1，则应删除table1中的某些条目，否则删除不同的条目。我的功能如下：

function reset_db
{
        if [ $usr_input == 1 ]  
        then
        sqlplus -s $USR/$pwd@$SID << EOF

        delete from table1 where component = 'ABC';
        delete from table2 where component = 'ABC';
        exit
EOF
        else if [ $usr_input == 2 ]

        delete from table1 where component = 'XYZ';
        delete from table2 where component = 'XYZ';
        exit
EOF
fi
}

我收到错误：语法错误接近意外令牌`fi'

我确信它正在发生，因为我在某处使用if-else错误，但无法找到修复它的方法。

另外，如果我有更多跟进问题，请告诉我如何在同一个帖子下发布代码。

Answer 1

你的'else if'错了，正确的语法是'elif'。

Answer 2

您需要在if语句的每个子句中重复该命令：

function reset_db
{
        if [ $usr_input == 1 ]  
        then
        sqlplus -s $USR/$pwd@$SID << EOF

        delete from table1 where component = 'ABC';
        delete from table2 where component = 'ABC';
        exit
EOF
        elif [ $usr_input == 2 ]; then

        sqlplus -s $USR/$pwd@$SID << EOF
        delete from table1 where component = 'XYZ';
        delete from table2 where component = 'XYZ';
        exit
EOF
fi
}

作为简化，你应该重构：

reset_db () {
    if [[ $usr_input = 1 ]]; then
      to_delete='ABC'
    elif [[ $usr_input = 2 ]]; then
      to_delete='XYZ'
    else
      return
    fi
    sqlplus -s "$USR/$pwd@$SID" <<EOF
    delete from table1 where component = '$to_delete'
    delete from table2 where component = '$to_delete'  
    exit
EOF
    fi
}

如果在bash中如何做sqlplus？

2 个答案: