# Models
class User < ActiveRecord::Base
has_many :items
end
class Items < ActiveRecord::Base
belongs_to :user
validates_presence_of :user_id
end
# Factories
Factory.define(:user) do |u|
u.name "foo"
end
Factory.define(:user_with_items, :parent => :user) do |u|
u.items {|items| [items.association(:item), items.association(:item)]}
end
Factory.define(:item) do |i|
i.color "red"
end
Factory.define(:item_with_user, :parent => :user) do |i|
i.association(:user)
end
如果您运行@user = Factory(:user_with_items)
,则@user.items
包含这两项。问题是项目与数据库中的用户无关。如果你重新加载关联@user.items(true)
,那么你会得到一个空数组。我知道你可以建造它们
手动或自己创建辅助方法来构建对象图,但我想避免这种情况。
所以,我的问题是如何在尊重构建策略的同时在factory_girl中建立一个has_many关系?
答案 0 :(得分:18)
答案 1 :(得分:11)
我最终修补工厂女孩以允许after_build
和after_create
回调。
Factory.class_eval do
def run (proxy_class, overrides) #:nodoc:
proxy = proxy_class.new(build_class)
proxy.callbacks = @callbacks
overrides = symbolize_keys(overrides)
overrides.each {|attr, val| proxy.set(attr, val) }
passed_keys = overrides.keys.collect {|k| Factory.aliases_for(k) }.flatten
@attributes.each do |attribute|
unless passed_keys.include?(attribute.name)
attribute.add_to(proxy)
end
end
proxy.result
end
def after_create(&block)
@callbacks ||= {}
@callbacks[:after_create] = block
end
def after_build(&block)
@callbacks ||= {}
@callbacks[:after_build] = block
end
end
Factory::Proxy.class_eval do
attr_accessor :callbacks
def run_callback(name)
callbacks && callbacks[name] && callbacks[name].call(@instance)
end
end
Factory::Proxy::Build.class_eval do
def result
run_callback(:after_build)
@instance
end
end
Factory::Proxy::Create.class_eval do
def result
run_callback(:after_build)
@instance.save!
run_callback(:after_create)
@instance
end
end
这可能是一个邪恶的双胞胎或只是你需要的扩展。
# Models
class User < ActiveRecord::Base
has_many :items
end
class Items < ActiveRecord::Base
belongs_to :user
validates_presence_of :user_id
end
# Factories
Factory.define(:user) do |u|
u.name "foo"
end
Factory.define(:user_with_items, :parent => :user) do |u|
u.after_build do |o|
o.items = [Factory.build(:item, :user => o), Factory.build(:item, :user => o)]
end
end
Factory.define(:item) do |i|
i.color "red"
end
Factory.define(:item_with_user, :parent => :user) do |i|
i.association(:user)
end
# Run
user = Factory(:user_with_items)
user.items(true) # Shows the two saved items
希望这可以帮助将来的某个人。我可能会尝试将这个提交给thinkbot上的那些人,但是他们已经在他们的bug跟踪器中有关于该主题的几张过时的票。
答案 2 :(得分:5)
我通常喜欢将构建和创建分开,所以我仍然可以在不进入数据库的情况下构建对象。
Factory.define(:user_with_items, :parent => :user) do |u|
u.after_build do |u|
u.items = (1..2).map {Factory.build(:item, :user => u)}
end
u.after_create do |u|
u.items.each {|i| i.save!}
end
end