Question

我有一个HTML字符串，如下所示：

$string = "\n<h2>heading 2</h2>\n\nwhatever we are doing is good to have one thing\n<h3>heading 3</h3>\nnext paragraph goes there\n<h2>new heading 2</h2>\n\npara succeeded for new heading 2\n\n<h2>heading 3</h2>\nand the rest of data";

我想要标题文字（即＆lt; h2＆gt;和＆lt; / h2＆gt;标记内）和后续文字（直到它找到另一个＆lt; h2＆gt;）或字符串结尾

我尝试过类似的事情：

$pattern = "/<h2>((?:(?!(<\/h2>)).)*)<\/h2>(.*?)(<h2>)?/is";

但这并没有带来预期的结果。

我想得到如下：

Array
(
[0] => Array
    (
        [0] => <h2>heading 2</h2>
        [1] => <h2>new heading 2</h2>
        [2] => <h2>heading 3</h2>
    )

[1] => Array
    (
        [0] => heading 2
        [1] => new heading 2
        [2] => heading 3
    )

[2] => Array
    (
        [0] => whatever we are doing is good to have one thing\n&lt;h3&gt; heading 3&lt;h3&gt;/h3&lt;h3&gt;\nnext paragraph goes there
        [1] => para succeeded for new heading 2
        [2] => and the rest of data
    )
)

Answer 1

试试这个

preg_match_all('#<h2>(.*)</h2>([^<]*+)#isU', $string, $match);
echo '<pre>' . htmlspecialchars(print_r($match, 1)) . '</pre>';

或许这样你需要

preg_match_all('#<h2>(.*)</h2>((?:(?!<h2>).)*+)#isU', $string, $match);

优化版

$pattern = '#<h2>(.*)</h2>(.*)(?=(?:<h2>|$))#isU';

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1 个答案: