好吧,我的登录代码有点麻烦。所有工作都很棒,但是当我试图从我的用户那里获取行时,它会显示第一个用户的行(我的意思是信息)关于用户名,密码,电子邮件,...)。
public function login($username, $password){
global $pdo;
$query = $pdo->prepare("SELECT * FROM users WHERE username = ? AND password = ?");
$query->bindValue(1, $username);
$query->bindValue(2, $password);
$query->execute();
$result = $query->rowCount();
if($result === 1){
return true;
} else {
return false;
}
}
我不能使用mysql_result,但我怎么能这样做呢?
function user_id_from_username($username){
return mysql_result(mysql_query("SELECT user_id FROM users WHERE username = $username"), 0, 'user_id');
}
function login($username, $password){
$user_id = user_id_from_username($username);
return (mysql_result(mysql_query("SELECT COUNT(user_id) FROM users WHERE username = $username AND password = $password "),0) == 1)? $user_id : false;
}
对不起我的englsih ^^
答案 0 :(得分:0)
public function login($username, $password){
global $pdo;
$query = $pdo->prepare("SELECT id FROM users WHERE username = ? AND password = ?");
$query->execute(array($username, $password));
return $query->fetchColumn();
}